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Do we integrate the equation :S should we open the brackets first?This a long but easy question .
View attachment 53151 Can someone please do part 1. Thanks
TrueThanks , but it didn't need that much working , it only carries one mark .
I got it by 1100 x 10 x ( 160/1760)x directly.![]()
I took AB as rcosx..... plz explainQ6) I)First off, were told that perimeter of shade= 1/2 circle circumference
Find radius of shade by dropping down a perpendicular so you get this in terms of r and x. Also theta here will be 2x. Radius of shade we do cosx= Adj/r , hence adj = rcosx and so side AB= 2rcosx
Also side AC is 2rcosx
So Perimeter Shade= 1/2 Circle Circumference Get arc length = rtheta = 2rcosx 2x= 4rxcosx
Arc + AB + AC= 1/2 x 2pier
4rxcosx + 2rcosx + 2rcosx= pier
Cross r
4xcosx + 4cosx = pie Notice on left hand side cosx is a common factor
So cosx(4x + 4) = pie
Cosx= pie/(4x + 4)
X = cosinverse(pie/4x+4)
Horrible :/how was p1? (don't discuss)
How was it for you? and which variant?how was p1? (don't discuss)
Thanks :/ pata nai kesa huaCh 2 - http://www.examsolutions.net/maths-revision/syllabuses/CIE/period-1/P1/module.php
It'll be very easy once u see all of these videos of Ch - 2 Functions.
All the best Asmu ^_^
Very easy.how was p1? (don't discuss)
U cant discuss before 24 hours. U can Message me if u want to discuss.I GAVE VARIANT 12 MATHS ALEVELS?
HOW WAS IT GUYS?
I WANT TO DISCUSS.
Inbox!where can I message?
^ Integration Question32/3 pi. The Ans for the Volume Q
16/3 pi32/3 pi. The Ans for the Volume Q
Seriously? Well I got the ans in -ve and since Vol can't be -ve I wrote it as positive and plus every class has a genius guy so he too got the same ans.16/3 pi
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