- Messages
- 329
- Reaction score
- 505
- Points
- 103
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
How do we calculate V for the first part?
Ive uploaded mark scheme as well
i saw the mark scheme but it was pretty confusing can anyone please tell me how to form an equation as well?
Driving force = P/V
P/V - Fr = ma
30000/Vinitial - 12500(30/500) - 1000 = 1250(4)
and
30000/Vfinal -12500(30/500) - 1000 = 1250(0.2)
component of weight down the slope.Whats - 12500 (30/500) ?
component of weight down the slope.
component is mgsin(theta)I dont understand, how did you get that? :s
Ohhh, got it! thankyou so much!component is mgsin(theta)
mg is 12500
For sintheta, consider the triangle in the question. Length of the slope(500) is hypotenuse and the height(30) is the perpendicular. sin(theta) = 30/500
so the component is 12500(30/500)
Velocity after A is 10t - 0.15t^2 +C (Integrated acceleration)
jazak Allah khair, thank you
Pray for mejazak Allah khair, thank you![]()
![]()
Insha Allah, pray for me too!Pray for me
And ignore the top line of 2nd page![]()
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now