- Messages
- 138
- Reaction score
- 31
- Points
- 38
ii)Take 2 out.
2 ʃ ((2-u)^2 / u) du
Solve the square.
2 ʃ (4 - 4u +u^2)/u
Make fractions.
2 ʃ 4/u – 4u/u + u^2 /u)
Cancelling out will give you.
2 ʃ 4/u – 4 + u
Now integrate.
2 [ 4ln IuI – 4u + u^2/2 ]
8ln IuI - 8u + u^2
Plug in the limits.
(8ln I2I – 8(2) + (2^2)) – (8ln I1I – 8(1) + 1^2)
(8ln I2I – 16 + 4) – (0 – 8 + 1)
(8ln I2I – 12) – ( - 7)
8ln I2I - 12 + 7
8ln I2I – 5 Ans.
Thanks a lot