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Yes, I included that possibility as well and got 3990 for the last part of combinations.. How you got 3990 with just 3? I don't remember how many possibilities were there but they weren't 3 just, but yes I did include the one you mentioned..
Then maybe i did include that possibility but just cant remember it
Hey are you sure your answer for the second part of permuatation's question is correct? Because I did it the same as you did it (first taking 3Ls between 2Ws then 2Ls then 1L ) . My ans was 20160 .
I guess I'm sure. How did you do?Hey are you sure your answer for the second part of permuatation's question is correct? Because I did it the same as you did it (first taking 3Ls between 2Ws then 2Ls then 1L ) . My ans was 20160 .
7.8 something...
I did good except for this permutation's question. Well its 4 marks so I guess its not a big deal. I might even score 2/4 for the method marks.
7.8 something...
I did good except for this permutation's question. Well its 4 marks so I guess its not a big deal. I might even score 2/4 for the method marks.
im pretty sure I had 4 possibilities. How many did you have?
I don't remember. My answer was 3990, that's what I remember only.
3 marks
What was your answer?yep there were 4 possibilities
Great3 marks
yep there were 4 possibilities
Btw, we had to use normal distribution like 3 times right?
4 times I think..... Thrice in Q6 for all three parts and once for normal approximation..Great
3 marks
yep there were 4 possibilities
Okay good, haha.
I did the same maybe 1/4 marks mil jaeinFor the 2nd part of permutations I got 8P6 because between the 2 Ws only 6 letters could come and 8 were left. And on either side of each W there could be 2 remaining letters so 2! (those 2 letters shuffled) and then those 2 could be on either side. So 8P6 x 2! x 2!. How many marks do you guys think I'll get out of 4?
I did 2! x 8P6/3! X 2!
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