- Messages
- 2,797
- Reaction score
- 2,035
- Points
- 273
Oh sorry, I stand corrected; I made a mistake of adding 10% to the sales price. Its fixed. 10% commission if he sells 10 or more, 25% commission if he sells 50 or more.how m not getting it
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Oh sorry, I stand corrected; I made a mistake of adding 10% to the sales price. Its fixed. 10% commission if he sells 10 or more, 25% commission if he sells 50 or more.how m not getting it
Have you solved the chapter from classified?
sorry but I thought you were talking about maths,I dont take addmaths so I guess I cant guide you here
Then you must know that in evety question we get a perfect fit (or near perfect) so that question is one out of the bloom I guess.
PQ = 7 cm , MN = 14 cmplease help with these questions
XY= 16 cm, NP = 2 cm, OP=OX=OY (radii)please help with these questions
Yes, they are the same since they both have the same transformation matrices.Look at these two transformations:
1. Stretch with y-axis as invariant line and stretch factor of -1.
2. Reflection in the y-axis.
Aren't 1 and 2 the same?
yay i had tried this yesterday and its correctPQ = 7 cm , MN = 14 cm
Let A and B be midpoints of MN and PQ respectively.
Therefore AB = 3 cm (given), PB=BQ=3.5 cm, MA=AN=7cm
Now,
Considering Triangle OAN,
Let OA=x, ON=r,
Using Pythagoras Theorem,
(ON)^2=(OA)^2+(AN)^2
(r)^2=(x)^2+(7)^2
(r)^2=(x)^2+49...... (i)
Considering Triangle OBQ,
OB=x+3, OQ=r (same radius as ON)
Using Pythagoras Theorem,
(OQ)^2=(OB)^2+(BQ)^2
(r)^2=(x+3)^2+(3,5)^2....... (ii)
Solving Simultaneously,
(x)^2+49=(x)^2+6x+9+12.25
6x=27.75
x=4.625 cm
From (i),
(r)^2=(4.625)^2+49
(r)^2=70.39
r=8.39 cm (3 sig. fig.)
See diagram for better understanding.
View attachment 23460
Then how do we answer Q11(a-iv) ? Why not in terms of stretch?Yes, they are the same since they both have the same transformation matrices.
PQ = 7 cm , MN = 14 cm
Let A and B be midpoints of MN and PQ respectively.
Therefore AB = 3 cm (given), PB=BQ=3.5 cm, MA=AN=7cm
Now,
Considering Triangle OAN,
Let OA=x, ON=r,
Using Pythagoras Theorem,
(ON)^2=(OA)^2+(AN)^2
(r)^2=(x)^2+(7)^2
(r)^2=(x)^2+49...... (i)
Considering Triangle OBQ,
OB=x+3, OQ=r (same radius as ON)
Using Pythagoras Theorem,
(OQ)^2=(OB)^2+(BQ)^2
(r)^2=(x+3)^2+(3,5)^2....... (ii)
Solving Simultaneously,
(x)^2+49=(x)^2+6x+9+12.25
6x=27.75
x=4.625 cm
From (i),
(r)^2=(4.625)^2+4
(r)^2=70.39
r=8.39 cm (3 sig. fig.)
See diagram for better understanding.
Yeah, our book doesn't have them either. Our teacher solved questions and helped us with these topics.i always thought that integration by parts, u-substitution and trig substitution are not in syllabus as they are not in book but i recently saw a question which has to be done by u-substitution. so does it mean that others are also included(by parts and trig substitution)
Yeah, our book doesn't have them either. Our teacher solved questions and helped us with these topics.
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now