Maths, Addmaths and Statistics: Post your doubts here!

[Master Killer]

Please help me with these Statistics Past Papers Problems
1. November 2012/12: Q7 ii
2. " 2012/12: Q11 c
3. " " /13: Q7 b and c
4. " " /13: Q10 b (i) (Standard Deviation) and Q10b(ii)
5. " " /13: Q6 (iv)
6. " " /22: Q6(ii)
7. " " /22: Q7(iii) and (iv)
8. " " /22: Q9(b)
9. " " /23: Q7(iii)
10. " " /23: Q9(ii)(b)(c) and (iii)
11. " " /23: Q10(i) , (ii)b , (iii) (b) , (iv) (b) and (v)

 

[Asad.Babur]

Five competitors in a quiz are isolated from each other. They are asked, in a random order, the
same question, until one of them gives the correct answer.
At this point the questioning stops. Two of them know the correct answer, and three do not.
(i) State the maximum number of times the question would have to be asked.
PLZ HELP ASAP.

4

 

[Asad.Babur]

Please help me with these Statistics Past Papers Problems
1. November 2012/12: Q7 ii
2. " 2012/12: Q11 c
3. " " /13: Q7 b and c
4. " " /13: Q10 b (i) (Standard Deviation) and Q10b(ii)
5. " " /13: Q6 (iv)
6. " " /22: Q6(ii)
7. " " /22: Q7(iii) and (iv)
8. " " /22: Q9(b)
9. " " /23: Q7(iii)
10. " " /23: Q9(ii)(b)(c) and (iii)
11. " " /23: Q10(i) , (ii)b , (iii) (b) , (iv) (b) and (v)

Too Late,

 

[Master Killer]

Too Late,

You can see when I posted the message. I was not late, you are late. But anyway paper went too good

 

[Asad.Babur]

You can see when I posted the message. I was not late, you are late. But anyway paper went too good

mine too, your EXPECTATION ???

 

[uclesstudnt]

Hello, may I ask you guys something? Can you tell me what angles did you get for this question?
Find x, for which if Sin -x = -0.5 . Your reply is greatly appreciated.

 

[Master Killer]

mine too, your EXPECTATION ???

A* Inshallah and Yours?

 

[Fate0]

Hello, may I ask you guys something? Can you tell me what angles did you get for this question?
Find x, for which if Sin -x = -0.5 . Your reply is greatly appreciated.

-x = Sin ^-1 (-0.5)
-x = -30 and -150
Hence , x = 30, 150. I think thats it

 

[Muhammad Saad :)]

XPF members l am facing trouble solving questions about ascending and descending values in maths e.g. arrange these values in ascending order starting from the smallest 0.6,0.67,66/100,666/1000,6^0..??please help..thanks

 

[Ayyan :D]

XPF members l am facing trouble solving questions about ascending and descending values in maths e.g. arrange these values in ascending order starting from the smallest 0.6,0.67,66/100,666/1000,6^0..??please help..thanks

0.6, 66/100, 666/1000, 0.67, 6^0

 

[mikail]

Sin( -x ) = - sin (x)

 

[mikail]

- sin (x) = -0.5
sin (x) = 0.5

 

[Muhammad Saad :)]

0.6, 66/100, 666/1000, 0.67, 6^0

How do we determine whether o.6 is bigger value or 0.7 and 0.66?

 

[mikail]

u can do a number line ...

 

[mikail]

After 0.6, you get 0.7. In between 0.6 and 0.7, u get 0.66.
So, 0.6 is less than both 0.66 and 0.7.

Do this on a number line. You will understand it better visually.

 

[Ayyan :D]

How do we determine whether o.6 is bigger value or 0.7 and 0.66?

Use the number line method.
And add a zero to the end, to make it more understandable.

0.6 = 0.60
0.7 = 0.70
0.66 = 0.66

You can easily see, that 0.60 is smaller than 0.66 and that is smaller than 0.70
Hence, 0.6, 0.66, 0.7 is the sequence.

 

[Muhammad Saad :)]

Thanks guys that helped a lot @Ayyan and mikail

 

[Muhammad Saad :)]

Thanks guys that helped a lot @Ayyan and mikail

 

[Ram97]

Help needed
http://papers.xtremepapers.com/CIE/...Calculator Version) (4024)/4024_w12_qp_12.pdf
Q.25 part b (i)

Also explain please

 

[Fate0]

I

Help needed
http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w12_qp_12.pdf
Q.25 part b (i)

Also explain please

In a Speed-Time Graph , the distance is given by the area under the graph.
Distance Provided = 40 m.
Area Under Graph = Trapezium Shaped , right ?

40 = 1/2 x (Height 1 + Height 2) x Base
40 = 1/2 x (u +3u) x 10
80 = 40u
2 m/s = u.

Checking Answer.
1/2 x (2+6) x 10 = 40 m

 

[Ram97]

I

In a Speed-Time Graph , the distance is given by the area under the graph.
Distance Provided = 40 m.
Area Under Graph = Trapezium Shaped , right ?

40 = 1/2 x (Height 1 + Height 2) x Base
40 = 1/2 x (u +3u) x 10
80 = 40u
2 m/s = u.

Checking Answer.
1/2 x (2+6) x 10 = 40 m

Thanks a lot, man!!!