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I also got infectedGood morning people - apologies for everything that transpired tommorow.
I was just infected by the gifsease.
I am happy to announce that now. I. am.
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still a part - get ready for more today.
but how is aoc equal to 2(86)?odc = 90 - 58 = 32
doc = 180 - 32-32 = 116
aoc = 86 * 2 = 172 ( angle at centre = 2 angle AT circumference )
doc = 172 - 116 = 56
bcd = 58 ( alternate angles )
bad = 180 - 58 = 122 ( opposite angles in a cyclic quad )
they are suspended by the same arc acb
but how is aoc equal to 2(86)?
how can this( angle at centre property ) be applied here :s
Almost understood it.
no dont......what if it comes in section AWhat if I skip Transformation for Paper 2? :/ There's choice.
Please, tell me. ._.
skipping anything in maths means death :3What if I skip Transformation for Paper 2? :/ There's choice.
Please, tell me. ._.
skipping anything in maths means death :3
:"/no dont......what if it comes in section A
this question came in our mock exams ....http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s13_qp_22.pdf
Question 4 (a)
The working given in the marking scheme is
(AF + 16) * 6 = 138
I mean even if this is a trapezium, don't we have to multiply it by 2 as there are 2 trapeziums?
***amd***
Ughh yeahthis question came in our mock exams ....
so the area of the trapezium = 1/2 *height * (sum of parallel sides )
so we multiply it by 2 and then get ... 6 * (af + 16 )
there are two trapeziums making an area if 138.http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s13_qp_22.pdf
Question 4 (a)
The working given in the marking scheme is
(AF + 16) * 6 = 138
I mean even if this is a trapezium, don't we have to multiply it by 2 as there are 2 trapeziums?
***amd***
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