Maths, Addmaths and Statistics: Post your doubts here!

[M.Omar]

Well i derived since there are only 2 angles,38 and 106 it must be smaller one cuz its acute,but there is not sure way cuz it could be any value,but my only logical guess was 38.

well if u have in hard copy format check the size of the angles by protractor..do they also mathc .just wondering

 

[Dark Destination]

Yar hell with the question u can always do it a later time..U justed wasted abt an hour of ur study time!
exploded diper I guess is in it as well
Btw u called for it

2:13 ?

 

[M.Omar]

2:13 ?

It,s incorrect for either parts.sorry

 

[Dark Destination]

It,s incorrect for either parts.sorry

Okay, i'm the biggest loser on the planet.

 

[asadalam]

well if u have in hard copy format check the size of the angles by protractor..do they also mathc .just wondering

I dont have a hard copy,but they dont match on screen.But since images are still similar and only lengths are altered i guess angles would still be same on soft and hard copy,though i did notice something strange.On screen angle was 38 but on my protactor it was 28,but when i measured the 3,a.ii angle it was also identical and was 28 on my protactor so maybe that could help us out,in case angles are same....

 

[M.Omar]

Okay, i'm the biggest loser on the planet.

u r saying like u were the only to not do it.
Just return to ppr 2.there is always time after 29th

 

[M.Omar]

I dont have a hard copy,but they dont match on screen.But since images are still similar and only lengths are altered i guess angles would still be same on soft and hard copy,though i did notice something strange.On screen angle was 38 but on my protactor it was 28,but when i measured the 3,a.ii angle it was also identical and was 28 on my protactor so maybe that could help us out,in case angles are same....

a pt to note
na they cut marks anyway for no working

 

[Dark Destination]

u r saying like u were the only to not do it.
Just return to ppr 2.there is always time after 29th

Okay, i give up.. now that i have failed.

Can you tell me the answers now?

 

[era30amy]

http://papers.xtremepapers.com/CIE/...(Calculator Version) (4024)/4024_w07_qp_2.pdf

^Q-11 b) iii) b)

The one who solves it for me will get so many duas from the bottom of my heart. :3

 

[asadalam]

a pt to note
na they cut marks anyway for no working

Are you saying they cut or dont cut for no working.

 

[M.Omar]

Are you saying they cut or dont cut for no working.

they cut.

 

[asadalam]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w07_qp_2.pdf

^Q-11 b) iii) b)

The one who solves it for me will get so many duas from the bottom of my heart. :3

Interquartile is Upper Quartile(350 x 3/4) - (350 x 1/4)

So find Upper by multiplying as shown and finding value on which graph cuts on x-axis(join y with graph by a straight line and then drop it to get x- value)
Likewise find x of Lower and subtract lower from upper value.

That is interquartile range

 

[asadalam]

they cut.

Why?If of one mark and they dont ask us to show any reasoning,mark is only for correct answer....If they want reasons they ask,i saw it in a q.

 

[era30amy]

Interquartile is Upper Quartile(350 x 3/4) - (350 x 1/4)

So find Upper by multiplying as shown and finding value on which graph cuts on x-axis(join y with graph by a straight line and then drop it to get x- value)
Likewise find x of Lower and subtract lower from upper value.

That is interquartile range

You good? I am talking about question 11. =/

 

[Dark Destination]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w07_qp_2.pdf

^Q-11 b) iii) b)

The one who solves it for me will get so many duas from the bottom of my heart. :3

You have to make a general matrix equation.

Like the matrix of Transformation R they gave you.
Multiply it with (h,k).. and get the resultant in the form of h and k.
Then add translation matrix to it.. to get (-k-3,h-3)

 

[M.Omar]

Okay, i give up.. now that i have failed.

Can you tell me the answers now?

Nopes....

 

[asadalam]

You good? I am talking about question 11. =/

...

 

[***amd***]

***amd*** can u give the answer for the trapezium question.........
and was the question u gave the accurate drawing............

answer is 13.

 

[era30amy]

You have to make a general matrix equation.

Like the matrix of Transformation R they gave you.
Multiply it with (h,k).. and get the resultant in the form of h and k.
Then add translation matrix to it.. to get (-k-3,h-3)

Didn't get it one bit.

 

[asadalam]

Nopes....

What is the question?can you repost it??