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wht abt ur integration questionI don't understand :/
Why not that infinity thing?
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wht abt ur integration questionI don't understand :/
Why not that infinity thing?
because firstly it cud not be neg as range and domain of org function said so
secondly it was to be greater than 2 i.e domain of org f
and thus u cud write 2<f<infinity or simply f>2
because firstly it cud not be neg as range and domain of org function said so
secondly it was to be greater than 2 i.e domain of org f
and thus u cud write 2<f<infinity or simply f>2
I guess 2How many marks was the domain and range for? The total part was for 4 marks, that included finding the inverse.
coz it,s an inverse function of the original one...get it.there is no brand new one though u cud say it was new in the sense tht it was derived frm org and diff frm originalWait. Who said we have to link it the previous function?
This is a brand new function, with it's own graph, domain and range. Why are you linking it to the previous one?
wht did u get for integration questionWait. Who said we have to link it the previous function?
This is a brand new function, with it's own graph, domain and range. Why are you linking it to the previous one?
coz it,s an inverse function of the original one...get it.there is no brand new one though u cud say it was new in the sense tht it was derived frm org and diff frm original
I am sorry but tht is not a case of wht if....like I said check the past pprs topical of 2002 or before and u will see such questions!!!What if it was an independent function?
That would my answers be right?
Yea tht,s wht i got as well107/30
which question's answer is this?107/30
the integration one..1.5 to 0which question's answer is this?
guys what do you the think the grade boundaries will be this year? To give you a good idea, last years was 151- A* 2012 was 143- A* and 2011 was 151- A*? How was this paper in comparison to 2013,2012 and 2011? Any predictions as to what the grade boundaries will be like?
he is from igcseHOW DO YOU KNOW THAT? HOW DO YOU KNOW THAT? I REPEAT! HOW DO YOU KNOW THAT?
yeah I wrote the same tooHi guys, for the g(f(x)) question I answered something similar but worded it a bit differently. Do you mind taking a look at it? If. 2^2x-2^x=0 then 2^x=0,1 but for all x in real numbers 2^x cannot equal 0. Furthermore when 2^x=1 x=0 and when this is the case f(x)=0 as f(x)= 2^x - 1 and 2^0 - 1=0. But the range of f(x) is f(x)>3. So it is not possible that f(x)=0. So g(f(x))=0 has no solutions.
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