Maths, Addmaths and Statistics: Post your doubts here!

[beeloooo]

i have not done it..you want me to do it??

if u can !!

 

[ashiqbal]

http://clickpapers.net/past papers/math-/4024_s07_qp_1.pdf


q.14 last part !!
q.15 last part !!

help would be appreciated with explaination

area of shaded region = area of medium circle - area of smallest circle
= 4*pie*x^2 - pie*x^2 = 3(pie)x^2

let perpendicular distance from A to DE be x cm. then perpendicular distance from A to CB is x+4
use proportionality for similar triangles so that 9 : 12 :: x : x+4
3x=36
x=12
x+4 = 16

 

[beeloooo]

area of shaded region = area of medium circle - area of smallest circle
= 4*pie*x^2 - pie*x^2 = 3(pie)x^2

let perpendicular distance from A to DE be x cm. then perpendicular distance from A to CB is x+4
use proportionality for similar triangles so that 9 : 12 :: x : x+4
3x=36
x=12
x+4 = 16

Thanks

i got q.15 but still struggling to understand q.14 :O

 

[Spidey21]

Thanks

i got q.15 but still struggling to understand q.14 :O

its pretty simple try solving it and then see for yourself...

 

[beeloooo]

http://clickpapers.net/past papers/math-/4024_s09_qp_1.pdf


here u go another one q.13 ??? i have no idea about these graphs if anyone could guide me plz

thanks in advance !!

 

[asd]

area of shaded region = area of medium circle - area of smallest circle
= 4*pie*x^2 - pie*x^2 = 3(pie)x^2

let perpendicular distance from A to DE be x cm. then perpendicular distance from A to CB is x+4
use proportionality for similar triangles so that 9 : 12 :: x : x+4
3x=36
x=12
x+4 = 16

Funny how people think PI's spelling as Pie, even I used to think that way.

 

[beeloooo]

area of shaded region = area of medium circle - area of smallest circle
= 4*pie*x^2 - pie*x^2 = 3(pie)x^2

let perpendicular distance from A to DE be x cm. then perpendicular distance from A to CB is x+4
use proportionality for similar triangles so that 9 : 12 :: x : x+4
3x=36
x=12
x+4 = 16

OOPS !! i was finding the circumference where we had to find the area my bad !!

THANK YOU !

 

[ashiqbal]

Funny how people think PI's spelling as Pie, even I used to think that way.

acha acha, bus ziyada nahin !

 

[a.abid]

Hey everyone....how r u guys preparing for Maths?As in how many past papers r u doing?

 

[beeloooo]

Hey everyone....how r u guys preparing for Maths?As in how many past papers r u doing?

not good at p2 luv p1 and doing dem only from 02-11 !! im done with the june ones u ?

 

[a.abid]

not good at p2 luv p1 and doing dem only from 02-11 !! im done with the june ones u ?

gud job....I didnt do P2 yet but I am doing P1 randomly...

 

[Haris Bin Zahid]

http://clickpapers.net/past papers/math-/4024_s09_qp_1.pdf


here u go another one q.13 ??? i have no idea about these graphs if anyone could guide me plz

thanks in advance !!

(a) It is Figure 3. Bcz y-intercept seems to be 2, discriminant (b^2-4ac)<0 which means there are no real roots and the curve does not cut the x-axis. Moreover, the coefficient of x^2 is positive, means it has a minimum point.
(b) It is Figure 2. Equate the equation to 0. You'll get x=-1 and 2. Both these seem to be x-intercepts. The coefficient of x^2 is positive, so the curve has a minimum point.
(c) It is Figure 1. This is quite clear as only in this case, the coefficient of x^2 is negative (-1).....so the curve has a maximum point. The y-intercept is 2.....thus-justified.
Hope it helped

 

[beeloooo]

cmon guys !! do this last part of this paper

http://clickpapers.net/past papers/math-/4024_w10_qp_12.pdf

 

[haha101]

co linear points :
Please help me !!! And tell me about all the properties of colinear points !

And also the last two parts of transformation !

 

[kitecrystal]

can anyone plz explain the answers of questions 16(b)19(c)22(d) of june02 4024 paper1?em unable 2 find it online,so can not poat it.........

 

[Mayedah]

cmon guys !! do this last part of this paper

http://clickpapers.net/past papers/math-/4024_w10_qp_12.pdf

U have to make the equation

20- 2r = 40/360 x 2 x 3 x r
Solve it and u will get the answer which is 7.5 !

 

[Mayedah]

co linear points :
Please help me !!! And tell me about all the properties of colinear points !

And also the last two parts of transformation !

In transormation first u have to make a line joining corresponding points to find the invariant line...whenu will join thm u will find x= -1 as the invariant line now find the distance of any point of image from invariant line and divide it by the distance of the corresponding point of object to find stretch factor which will be 2

 

[haha101]

In transormation first u have to make a line joining corresponding points to find the invariant line...whenu will join thm u will find x= -1 as the invariant line now find the distance of any point of image from invariant line and divide it by the distance of the corresponding point of object to find stretch factor which will be 2

But how ? I dont understand ! Joining the points also gives me x=0 and x=-2 ! How do you know that its -1 ?

 

[HarisLatif]

http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_w11_qp_12.pdf
question no 18 part b

 

[beeloooo]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w11_qp_12.pdf
question no 18 part b

The b part is connected to part a !! the total time of the journey is 7.5 hours ryt !! for the first part of 5 hrs journey she travelled 150 km ~!! for the next 2.5 hours she will travel at 20 km/ h !! so distance would be = 20*2.5 = 50 km !! so now the average spped for the whole journey would equal = total distance / total time taken

which will be = 200/7.5 = 26.67 km / h !!

i haven't checked the mark scheme or anything + i am not sure i am ryt !! i tried to help !! do tell me whether its the rite answer or not