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Without using a calculator evaluate
(lg 5)^2+lg2 lg50
2(lg5) + lg5 lg20
2lg 10 + lg100
lg100 + lg100
After that I dont know.
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Without using a calculator evaluate
(lg 5)^2+lg2 lg50
Without using a calculator evaluate
(lg 5)^2+lg2 lg50
Do u need 4024(Syllabus D) or 4037(Add Math)?hey! i want some help...
i need past papers/links from before 2000 along with there er and ms
plz help!
thnx.
Asslamu Alikum Wa Rahmatullah Wa BarakatohoThnx a lot. I have a doubt here:
If a measurement is reported as 7 mm rounded to nearest mm, then its lower limit is obviously 6.50 mm but what is its upper limit? Is it 7.49 or 7.50?
http://www.mediafire.com/?az21dvjfvqga1 all winter 2012 papersAnyone can post the Nov 2012 Maths paper for O levels please....? secondly, make x the subject of formula.. x(x-2)=t-2
Thanks.
let me tell u an easy method. they say nearest to 'a' millimeter. mean 1 millimeter. divide 1 by 2. u get 0.5 millimeter. add it to the real value u get upper bound and subtract it u get lower bound.Thnx a lot. I have a doubt here:
If a measurement is reported as 7 mm rounded to nearest mm, then its lower limit is obviously 6.50 mm but what is its upper limit? Is it 7.49 or 7.50?
Assalamu AlikumPlease I need full explanation of this relative velocity question:
A coastguard station receives a distress call from a ship which is travelling at 15 km/h on a bearing of 150°. A lifeboat leaves the coastguard station at 15 00 hours; at this time the ship is at a distance of 30 km on a bearing of 270°. The lifeboat travels in a straight line at constant speed and reaches the ship at 15 40 hours.
(i) Find the speed of the lifeboat.
(ii) Find the bearing on which the lifeboat travelled.
PhyZac , scouserlfc , FAHMEED
Thanks a lot for sparing your precious time to answer my question.Assalamu Alikum
What are the answers?
Is the speed 60 km/h and bearing 310?
I cant understand Where did the 18 came from???. And by the way it's cube root not square root!!
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