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Maths, Addmaths and Statistics: Post your doubts here!

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Re: O'level Maths, Addmaths and Statistics help available he

Can anyone help me in Q4 of p2 2010 session 21... Plz its urgent
 
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Re: O'level Maths, Addmaths and Statistics help available he

hassankhan said:
Can anyone help me in Q4 of p2 2010 session 21... Plz its urgent
This is easy
mean=sum of all the values/no. of values

therefore
2.5=sum of all the values/48
2.5x48= 120
so now we know that sum of values was 120
question told us that both values are 5 so 5 + 5 = 10 and this will be added in the total
10 + 120 = 130 and the total values are now 50.
so mean = 130/50 = 2.6
 
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Re: O'level Maths, Addmaths and Statistics help available he

Any help 4 Q 5 part b 2010 ppr 21.
 
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hassankhan said:
Plz help in q 5(b) 2010 ppr 23.
If you are referring to the part ii then this goes like this.
You would have calculated the overall percentage increase in part i which is 13.1%. So the answer to the ii part will be that the standard will not be maintained because increase in income is 11% while increase in prices is 13.1%. 11-13.1=-2.1%. so value is negative . That is the family will have to reduce expences.
 
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Re: O'level Maths, Addmaths and Statistics help available he

In a grouped frequency table values of the variables are given in classes labelled 50 to under 60, 60 to under 70 ,70 to under 80. True lower and upper class limits of the sixty to under seventy clause.
a) Masses measured to the nearest kg
b) ages expressed in number of COMPLETE YEARS
c) the number of cars at a car park at the same time each day
 
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Re: O'level Maths, Addmaths and Statistics help available he

can anyone please explain me how to shear in transformation topic? i am so confused.... :%)
n tnx for helpin!
 
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Skywalker said:
In a grouped frequency table values of the variables are given in classes labelled 50 to under 60, 60 to under 70 ,70 to under 80. True lower and upper class limits of the sixty to under seventy clause.
a) Masses measured to the nearest kg
b) ages expressed in number of COMPLETE YEARS
c) the number of cars at a car park at the same time each day

Answers
a) 59.5 - 69.5
b) 60-70
c) 60 - 69
 
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Please explain Sir jee. Urgent help needed. Kal exam.
 
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plzz solve this one i have great in solving this type of question & plzz explain it too
from 2010 paper 22 qs (2)

2 In a grouped frequency table, values of the variable are given in classes labelled 50 – under 60,
60 – under 70, 70 – under 80, etc.
Insert, in the table below, the true lower and upper class limits of the 60 – under 70 class, if the
values are
(i) masses measured to the nearest kg,
(ii) ages expressed in number of complete years,
(iii) the number of cars in a car park at the same time each day.
 
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muzirox said:
plzz solve this one i have great in solving this type of question & plzz explain it too
from 2010 paper 22 qs (2)

2 In a grouped frequency table, values of the variable are given in classes labelled 50 – under 60,
60 – under 70, 70 – under 80, etc.
Insert, in the table below, the true lower and upper class limits of the 60 – under 70 class, if the
values are
(i) masses measured to the nearest kg,
(ii) ages expressed in number of complete years,
(iii) the number of cars in a car park at the same time each day.
Answers:
1. 59.5-69.5
2. 60-69
3. 60-69
 
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tahatehseen said:
muzirox said:
plzz solve this one i have great in solving this type of question & plzz explain it too
from 2010 paper 22 qs (2)

2 In a grouped frequency table, values of the variable are given in classes labelled 50 – under 60,
60 – under 70, 70 – under 80, etc.
Insert, in the table below, the true lower and upper class limits of the 60 – under 70 class, if the
values are
(i) masses measured to the nearest kg,
(ii) ages expressed in number of complete years,
(iii) the number of cars in a car park at the same time each day.
Answers:
1. 59.5-69.5
2. 60-69
3. 60-69

yar can uexplain this & ur ans to part (ii) is wrong
 
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Am I correct?
A bag contains 1 red, 1 blue and 3 green balls. Two balls are taken from the bag, at random, without replacement.
(a). write down the probability of the second ball being blue while the first is green./
(b). Expressing each answer in its simplest form, calculate the probability that
(i) both balls are green,
(ii) both balls are blue,
(iii) neither ball is green.


my answers.
(a). 1/3 as n(s) is 5. if two balls are taken so it becomes 3. and since there is only one blue ball so it becomes 1/3.
(b) (i). 3/5 x 1/3=1/5(simplest form).
(ii). 0. since there is only ONE blue ball.
(iii). (1st red x 2nd blue) + (1st blue x 2nd red)= (1/5 x 1/3) + (1/5 x 1/3)=2/15(simplest form).

Marking scheme answers.

(a).1/4
(b) (i). 3/10
(ii) 0
(iii) 1/10
 
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Re: O'level Maths, Addmaths and Statistics help available he

@princemaazthefinal :
(a)'Without replacement' tells you that only four balls are left now when the first is taken out. Out of these, only 1 is blue.
Therefore, P(second ball is blue) = 1/4

(b)(i) P(Both balls are green) = 3/5 x 2/4 = 3/10
(ii) You're correct here! :)
(iii) Neither ball is green can mean two things: First is red and second is blue or first is blue and second is red. The probabilities of these two scenarios are added to obtain the answer for this part.
P(Neither ball is green) = (1/5 x 1/4) + (1/5 x 1/4)
= 1/10.
 
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Re: O'level Maths, Addmaths and Statistics help available he

can anyone provide me some worksheets for maths please i need it urgent
 
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Re: O'level Maths, Addmaths and Statistics help available he

I don't know about worksheets but there's a lot of good websites you can get notes from. Here's one of them. There were also some good notes posted somewhere in this forum but that was long ago and they're probably buried somewhere deep down.. unless someone still has it and will be kind enough to upload it. :p
 
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Re: O'level Maths, Addmaths and Statistics help available he

thanks for that atleast you reply.. some people dont even bother replying
 
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can u scan ur worksheets... u might have some or ur friend
 
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