Maths, Addmaths and Statistics: Post your doubts here!

[black widow]

got it

since F, E, and D are collinear

FE=hFD, where h is a constant

q-p = h(p(3-4k) + 2kp)
-p+q = hp (3-4k) + 2hkq

comparing the coefficients of p and q

-1=h(3-4k) which implies -1 = 3h-4hk ... (1)

1=2hk which implies k=1/2h ... (2)

substitute (2) in to (1)

-1= 3h-4h (1/2h)

h= 1/3

substitute h=1/3 in to (2)

k=1/2(1/3)

k=1.5

 

[Nabeel.Ahmad]

got it

since F, E, and D are collinear

FE=hFD, where h is a constant

q-p = h(p(3-4k) + 2kp)
-p+q = hp (3-4k) + 2hkq

comparing the coefficients of p and q

-1=h(3-4k) which implies -1 = 3h-4hk ... (1)

1=2hk which implies k=1/2h ... (2)

substitute (2) in to (1)

-1= 3h-4h (1/2h)

h= 1/3

substitute h=1/3 in to (2)

k=1/2(1/3)

k=1.5

I'm a Loser.

 

[black widow]

I'm a Loser.

no its all right
it took me time as well to understand the collinear property

 

[LioxMessi]

got it

since F, E, and D are collinear

FE=hFD, where h is a constant

q-p = h(p(3-4k) + 2kp)
-p+q = hp (3-4k) + 2hkq

comparing the coefficients of p and q

-1=h(3-4k) which implies -1 = 3h-4hk ... (1)

1=2hk which implies k=1/2h ... (2)

substitute (2) in to (1)

-1= 3h-4h (1/2h)

h= 1/3

substitute h=1/3 in to (2)

k=1/2(1/3)

k=1.5

By collinear they meant that these points lie on the same straight line, and you did it right, we had to compare the coefficients.

 

[Nabeel.Ahmad]

no its all right
it took me time as well to understand the coefficient property

Oh. So you used the relation between FD and FE, that was h.. and the relation between BC and BC which was k.
And formed simultaneous equations, and solved them.

There were a total of 4 variables. So you compared the co-efficients. :O
And then two new equations were formed with only two variables.

Wow.

All this for only 2 marks, and that less space. ._.

 

[black widow]

Oh. So you used the relation between FD and FE, that was h.. and the relation between BC and BC which was k.
And formed simultaneous equations, and solved them.

There were a total of 4 variables. So you compared the co-efficients. :O
And then two new equations were formed with only two variables.

Wow.

All this for only 2 marks, and that less space. ._.

that is y i hate CIE
they make questions that take a really long time to solve and assign them very low marks, and make questions whose answers are only a line, providing like 4 lines, and give it high marks
they do this to confuse the candidates, especially those aiming for distinction, as like this the person seeking distinction questions himself over his answer, like has he written it in the most concisest manner or no

btw. the relation between FD and FE was supposed to be created
the other relation was already given

 

[Nabeel.Ahmad]

that is y i hate CIE
they make questions that take a really long time to solve and assign them very low marks, and make questions whose answers are only a line, providing like 4 lines, and give it high marks
they do this to confuse the candidates, especially those aiming for distinction, as like this the person seeking distinction questions himself over his answer, like has he written it in the most concisest manner or no

btw. the relation between FD and FE was supposed to be created
the other relation was already given

But you compared co-efficients. Why? Why was comparing co-efficients necessary?

Was this a tough question?

 

[Muhammad Saad :)]

Do we have Compound Interest in GCE O'Levels Syllabus?

 

[Nabeel.Ahmad]

Do we have Compound Interest in GCE O'Levels Syllabus?

No.

 

[funky brat]

No.

But they ask you to find the compound interest in so many questions, I was about to ask somebody to tell me the formula.

 

[Nabeel.Ahmad]

But they ask you to find the compound interest in so many questions, I was about to ask somebody to tell me the formula.

Never in the CIE papers.
Where did you see the questions? In the D-series books?

 

[funky brat]

Never in the CIE papers.
Where did you see the questions? In the D-series books?

Shukar hai.
I saw them in Classified.

 

[Nabeel.Ahmad]

Shukar hai.
I saw them in Classified.

Well, my teacher told me its not in the syllabus.
Idk why you saw 'Compound Interest' Questions in Classified.

 

[funky brat]

Well, my teacher told me its not in the syllabus.
Idk why you saw 'Compound Interest' Questions in Classified.

This was exactly what I was told but I actually so many questions. You might have a look if you've got Classified.

 

[Nabeel.Ahmad]

This was exactly what I was told but I actually so many questions. You might have a look if you've got Classified.

Okay, i'll take a look at it.

 

[Salman Shah Jee]

Notes for Everyday Mathematics(maths O levels).........

 

[Lilly2318]

Shukar hai.
I saw them in Classified.

i too hvnt seen any question but here is the formula
Compound Interest:

 

[Lilly2318]

where A is the total amnt of money ernd plus interest

 

[Lilly2318]

I hv problem in a) part im apllying the( x/360 into pie r square) formula yet the answer coming is 9pie/8 where as in mar
king scheme is 5pie/8

 

[Dark Destination]

I hv problem in a) part im apllying the( x/360 into pie r square) formula yet the answer coming is 9pie/8 where as in mar
king scheme is 5pie/8

You're calculating the total area, they asked for the shaded area.
SHADED AREA. The one in grey-ish color.

You have to subtract the small sector area from big sector area.