Maths, Addmaths and Statistics: Post your doubts here!

[Izhaan]

Can anyone plz give me o lvl maths complete formula sheet?

 

[Awesome12]

Thanks
btw have you got any detailed notes on this topic?
Although i know all the properties but still i'm not able to solve Qs of this topic (?_?)

the questions are a bit tricky but before solving the past papers u need to solve questions that need u to apply only some of the rules rather than the whole set
after that u can move on to past papers
the trick is to visualize the diagram in every possible way and apply each of the rules to it
for example, if in the diagram there is a tangent to a circle and a line passing from the centre of the circle is touching the tangent, u can easily apply the rule
''the angle between the tangent touching the circle and the line passing from the centre of the circle is 90 degrees'

 

[Maganius]

the questions are a bit tricky but before solving the past papers u need to solve questions that need u to apply only some of the rules rather than the whole set
after that u can move on to past papers
the trick is to visualize the diagram in every possible way and apply each of the rules to it
for example, if in the diagram there is a tangent to a circle and a line passing from the centre of the circle is touching the tangent, u can easily apply the rule
''the angle between the tangent touching the circle and the line passing from the centre of the circle is 90 degrees'

great^_^
Thanks

 

[Awesome12]

cud anyone tell me how to find a and b with all the steps

 

[Awesome12]

Dark Destination

 

[Dark Destination]

Awesome12

AOB = 128.
And if an angle from chord AB was subtended at the circumference, it would be half of 128 that is 64.
That will form a cyclic quadrilateral, and AQB = 180 - 64 = 116.

Then, 116 + 5a + 3a = 180
8a = 64
a = 8.

Then, you will look at triangle AQP.
116 + 3(8) + b = 180
140 + b = 180
b = 40

 

[***amd***]

Awesome12

AOB = 128.
And if an angle from chord AB was subtended at the circumference, it would be half of 128 that is 64.
That will form a cyclic quadrilateral, and AQB = 180 - 64 = 116.

Then, 116 + 5a + 3a = 180
8a = 64
a = 8.

Then, you will look at triangle AQP.
116 + 3(8) + b = 180
140 + b = 180
b = 40

you got wrong for b

 

[Awesome12]

Awesome12

AOB = 128.
And if an angle from chord AB was subtended at the circumference, it would be half of 128 that is 64.
That will form a cyclic quadrilateral, and AQB = 180 - 64 = 116.

Then, 116 + 5a + 3a = 180
8a = 64
a = 8.

Then, you will look at triangle AQP.
116 + 3(8) + b = 180
140 + b = 180
b = 40

thnx dude

but b is wrong, there is angle bqp as well that shud be added to 116 but u haven't added it

 

[Dark Destination]

thnx dude

but b is wrong, there is angle bqp as well that shud be added to 116 but u haven't added it

b = 16?

 

[Awesome12]

b = 16?

yes but how?

 

[***amd***]

b = 16?

yeah .

 

[Awesome12]

HOW?

 

[***amd***]

yes but how?

BQP = QAB it's a rule there.

 

[Dark Destination]

yes but how?

I wasn't paying attention to the question, so i forgot to add BQP.

BQP = 3a. (Alternate Segment Theorem)
QBP = 180 - 5a

Since, a = 8

24 + (180 -40) + b = 180
24 + 140 + b = 180
b = 180 - 164
b = 16

 

[***amd***]

BQP = QAB it's a rule there.

angle between a chord and a tangent = the angle extended from the chord to circumference.

 

[Awesome12]

angle between a chord and a tangent = the angle extended from the chord to circumference.

ok thats a new rule
thnx btw.

 

[***amd***]

ok thats a new rule
thnx btw.

its what my teacher told me, though i cant find it in my book. That's why i was cautious to try it.

 

[***amd***]

what is an identity matrix? ._-
abdxyz

 

[asadalam]

what is an identity matrix? ._-
abdxyz

As far as O level is concerned,its

10
01


matrix.If multiplied with any other matrix,the matrix will be unchanged.Also if any matrix is multiplied with its inverse,you will obtain an identity matrix.

 

[asadalam]

Please explain Q10s each part.