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Maths, Addmaths and Statistics: Post your doubts here!

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A model of a car is made to a scale of 1/40.
a, the height of the actual car is 1.5m. Find the height in cm of the model.
b, The luggage capacity of the model is 5 milliliters.
Find the luggage capacity in litres, of the actual car.
Anyone able to do the part b?
 
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A model of a car is made to a scale of 1/40.
a, the height of the actual car is 1.5m. Find the height in cm of the model.
b, The luggage capacity of the model is 5 milliliters.
Find the luggage capacity in litres, of the actual car.
Anyone able to do the part b?
We have to use similarity concept here

ratio of simple length is 1:40 s0 ration of volumes would be 1:40^3 that is 1:64000
That means that 1 milliliter in model will equal 64000 milliltres in the car.
We will multiply it by 5 since it says model has that much milliltres.Ans will be 320000 milliLITRES(not meters)
There are 1000ml in 1 l so we will divide it by 1000 and ans will be 320 litres :)
 
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A model of a car is made to a scale of 1/40.
a, the height of the actual car is 1.5m. Find the height in cm of the model.
b, The luggage capacity of the model is 5 milliliters.
Find the luggage capacity in litres, of the actual car.
Anyone able to do the part b?
Use the concept of similar volumes here

The ratio is 1: 40
The capacity of the model is 5 milliliters. It will have a unit length of 1 as it is smaller

so

5 ........ ( 1 ) ^ 3
--- : ........ ( -- )
x ....... ( 40)

x is 32000

1 liter is 1000 milliliters

So in liters, it will become 32000/1000 = 320 l
 
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