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yepIs this correctView attachment 43851
Isn't this shaded in the mark scheme?Is this correctView attachment 43851
Agar hota to pochta =pIsn't this shaded in the mark scheme?
ca= ab-b^2c = b(a – b)
........--------
..........a
How to make a the subject?
(P.S. Ignore the dots. It's just b(a-b) divided by a).
Link to paper/question?MS says:
a = b^2
.....-----
......b - c
Not really, I have other subjects too!Why not practice? There is still plenty of time.
Oh sorry a^2/b-c he hai, I made an error while writing.MS says:
a = b^2
.....-----
......b - c
Sab sey achi meri aur era30amy ki hai. :')Thanks alot :3 How is everyone's prep? Mine's awful - Transformation, Graphs and Mensuration still to go (Though I completed them in 1 hr during Mocks :3). Was busy for a few days :/
Manhoosest thing ever. .-.Worried about graphs and transformation. Rest are pretty okay.
abb kitnay aa jatay hain?Sab sey achi meri aur era30amy ki hai. :')
theek hai jab tum logon ko samajh aa jaye to mujhay bhi bata dena...discussion jaree hai bhai, intezar kro
Kiskay meray?abb kitnay aa jatay hain?
I can bet atleast more than 75 after these days
how in step 2 did b^2 get +ve and ca -ve ....Solved it anyway.
It's
ca = ba - b^2
ba - ca = b^2
a (b-c) = b^2
a = b^2 / b-c
I forgot about factorization here.
And Asad - it's M/J 12 - P12.Q11 b
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