t = 49.0Can someone tell me the time required for population(N) to double?
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t = 49.0Can someone tell me the time required for population(N) to double?
i dont remember but first we have to convert in partial fraction and then solve.....in partial i think 1 value is 50 and other is -1/2what was answer of the differential equation question?? was value of C equal to 50ln[1/4]
That part involved some tedious working, which was prone to algebraic errors. You just needed to express the complex number in polar form and then multiply the denominator and numerator with the conjugate of the denominator. After some pathetic amount of working, you had to apply the identities sin2x = 2(sinx)(cosx) AND cos2x = 2(cosx)^2 -1. That would finally give you the answer. But I think that question wasn't worth 4 marks. It was more.ooh i get it now thanks. it was freakin wasy.. i was just harrased :/
and what about that complex no did you get itan(theta)
yeah i got to much near it wasted quater of an hour on itThat part involved some tedious working, which was prone to algebraic errors. You just needed to express the complex number in polar form and then multiply the denominator and numerator with the conjugate of the denominator. After some pathetic amount of working, you had to apply the identities sin2x = 2(sinx)(cosx) AND cos2x = 2(cosx)^2 -1. That would finally give you the answer. But I think that question wasn't worth 4 marks. It was more.
sir i think the values were 1 and 1/2, maybe u r right, because only 2-3 people in my centre got the same answer as mine!!i dont remember but first we have to convert in partial fraction and then solve.....in partial i think 1 value is 50 and other is -1/2
bro it depends on what you made the two partial fractions from it doesnt matter it should both lead to the right equationsir i think the values were 1 and 1/2, maybe u r right, because only 2-3 people in my centre got the same answer as mine!!
and it would be appreciated if some brother solves the dif.....equation dN/dt=0.02N(1-0.01N)
t = 50ln(0.8N/20(1-0.01N))dN/dt = 0.02N(1-0.01N). N was 20 when t was 0.
Can someone solve the differential equation PLEASEE?
t = 50ln(0.8N/20(1-0.01N))sir i think the values were 1 and 1/2, maybe u r right, because only 2-3 people in my centre got the same answer as mine!!
and it would be appreciated if some brother solves the dif.....equation dN/dt=0.02N(1-0.01N)
if you found out the value of C wrong and left it in the unsimplified form (not in terms of t) how many would you get and i think it asked Nin terms of t :/t = 50ln(0.8N/20(1-0.01N))
You may get 4-6 out of 8. But now is not the right time to rue over what you've done. Pray to Allah for a good grade and prepare for the upcoming papers. You'll get what you deserve. InshaAllah.if you found out the value of C wrong and left it in the unsimplified form (not in terms of t) how many would you get and i think it asked Nin terms of t :/
dude its hard when you toiled and did 12 feakin years of past paper and then for this to hapen get 60+ in all the practice papers :/You may get 4-6 out of 8. But now is not the right time to rue over what you've done. Pray to Allah for a good grade and prepare for the upcoming papers. You'll get what you deserve.
i doubt thatt = 50ln(0.8N/20(1-0.01N))
Solve it for yourself then. I could be wrong. Solve it and then let me know.i doubt that
why so seriousSolve it for yourself then. I could be wrong. Solve it and then let me know.
You're in chill mood Leave this discussion for later.why so serious
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