Maths paper 2.. 2012!!

[Daxter]

When

did we have to use any formula? hw is the value 4 k 1.25? din we have to divide by 2?

there are parallel lines, the gradient is the same, so first we convert the equation in y=mx+c form, then we get k/2 = 5/4 so 10/4= k, so you get k as 2.5 or 5/2 or 10/4

 

[svenas]

For this, the ask u an equation for the line which passes through the origin(0,0), so u could only have 4 possible solutions(since it has to pass through origin) for this either y=0(which will be a horizantal line through), x=0(which will be a vertical line through 0), y=x, y=-x.
For y=x, y=-x, and y=o, these lines would interesect the graphs, thereby the answer is x=0

Also for cumulative frequency graphs do I've to start from 0 if the give me the first data as: t<=2 and c.f=24???
I'll appreciate ur answer

 

[IGCSE O/L student]

Also for cumulative frequency graphs do I've to start from 0 if the give me the first data as: t<=2 and c.f=24???
I'll appreciate ur answer

it's better 2 start frm 0.

 

[lamiji]

please any one does any one have any idea on to go about maths b paper 2
thanks

 

[IGCSE O/L student]

the answers x=0 in the mark scheme

k, thnx!

 

[IGCSE O/L student]

"Invariant" means doesn't change or permanent.. so if the shear is parallel to the x-axis the values change so its Y invariant, parallel to axis and invariant axis are the opposite things

wait until da markin scheme arrives!

 

[shafayat]

can u plz tell me me how is b) +3 and -3???

it was something like getting square root of 9 ... thus it was plus or minus 3

 

[shafayat]

guys what was the upper lower bound question if anyone remembers !! PLZ

 

[IGCSE O/L student]

guys what was the upper lower bound question if anyone remembers !! PLZ

cnt remember! sry!

 

[svenas]

cnt remember! sry!

hi how r u I've one more doubt in this 2011 m/j p43 q11 part(v)
I can't get how to solve it at all...
Thanks

 

[svenas]

Your welcome!
And thank you so much, I hope you get all A*s as well!
I guess your doubt got solved for that M/J 10 right?

Hi, plz help me in this question m/j 2011 p43 q11 part(v)
and thanks..

 

[IGCSE O/L student]

hi how r u I've one more doubt in this 2011 m/j p43 q11 part(v)
I can't get how to solve it at all...
Thanks

hey! fyn thnk u. wbu?

You have to find a formula for the nth term.​

When a sequence of numbers is given, ex:
3, 6,9,12,…
Find the difference. In this case, the difference between 3 and 6 is 3. The difference between 6 and 9 is 3, so we use "an + b" to find the formula. Using this, we have to form 2 possible formulas.
When n=1, and when n=2 (you can also form a formula when n=3, or 4, but I used when n=1, and 2)
In this case, when n=1, the formula is a+b=3
When n=2, the formula is 2a+b=6
Using elimination method or substitution method, find a and b. you then have the formula for the nth term.
If the difference between the numbers is not the same, ex: if the difference between the first and second is 1, n the difference between the second and third is 2, den we use "an^2 + bn + c"
Ex: if the sequence is 2,6,12,20,30,…
The difference between the first and second number is 4, the difference between the second number and the third number is 6, and the difference between the third number and the fourth number is 8. These differences arr not the same, so we find the difference of these numbers. The difference between 4 and 6 is 2, and the difference between 6 and 8 is 2, so we use "an^2+bn+c".We have to form 3 equations because we have to find the values of a, b and c.
When n=1, a+b+c=2
When n=2, 4a+2b+c=6
When n=3, 9a+3b+c=12
First use 2 of the equations:
The second minus the first will form: 3a+b=4
The third minus the second will form: 5a+b=6
(you can choose which of the equations you want to use to form the second set of equations. It doesn't necessarily have to be the second minus the first, and the third minus the second. It can also be the third minus the first, or any other way)
Find a and b using the newly formed equations, then substitute those values in one of the main equations to find the value of c. You now have the equation for the nth term of dis sequence.
Hope this has helped you!!!​

 

[shafayat]

Hi, plz help me in this question m/j 2011 p43 q11 part(v)
and thanks..

substitute 400 in the formula and then multiply the answer by two .. if u get it right ..plz reply

 

[IGCSE O/L student]

substitute 400 in the formula and then multiply the answer by two .. if u get it right ..plz reply

dis method is ryt. but i formed another formula

 

[shafayat]

dis method is ryt. but i formed another formula

wht anathor formula .. if u can plz share !!

 

[IGCSE O/L student]

wht anathor formula .. if u can plz share !!

i xplained hw to form it in my previous comment(da xtra long one)

 

[shafayat]

i xplained hw to form it in my previous comment(da xtra long one)

OMG that was very very helpful ... n also dumb of me not seeing it

 

[IGCSE O/L student]

OMG that was very very helpful ... n also dumb of me not seeing it

it's ok. glad 2 hv helped. pray 4 me plzzzz!

 

[shafayat]

i xplained hw to form it in my previous comment(da xtra long one)

btw how do u do it wen even the second difference is not the same .. n whts (an2)

 

[IGCSE O/L student]

btw how do u do it wen even the second difference is not the same .. n whts (an2)

dat typ of question is not dere for our level. if a question appears lyk dat, da formula will b given to use. it came in M/J 2011