• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Maths (Paper 3)

Messages
207
Reaction score
3
Points
0
please help me out in these two questions plzp lzplz plz urgent help!!!!
 

Attachments

  • Untitled.png
    Untitled.png
    45.2 KB · Views: 51
  • Untitled3.png
    Untitled3.png
    28.7 KB · Views: 51
Messages
286
Reaction score
228
Points
0
Madiha :) said:
can anyone please explain why only -0.5 is the answer ..
The easiest way to understand such problems is to use graphical method
Draw two lines:
y=2-3x
y=|x-3|
You will find that they only intersect at one point: x=-0.5
And |x-3| > 2-3x for all values of x greater than 0.5
 
Messages
760
Reaction score
10
Points
0
well madiha
if u square both sides u will get an anser of
-0.5<x<1.25
now chek if ur anser is correct
take for the range below -0.5 it will be incorrect
now take an x value of btween -0.5 and 1.25 it will be CORRECT
now take a value more than 1.25 it will also Be CORRECT
so we come to a conclusion that x can be greater than 1.25 so we eliminate that choice so all we get is
-0.5<x
 
Messages
760
Reaction score
10
Points
0
utsav
for the intergration
all u do is get the right R and theta values
after that all u must do is use the integral sec^2x intergrated is equal to tanx
 
Messages
286
Reaction score
228
Points
0
For solving modular equations:

1.
Check that you have the right number of solutions Be careful when solving equations involving a modulus function that you have the correct number of solutions. Sketching a graph is helpful, and you should also check your solution(s) by substituting back into the original equation.
2.
Take care with inequality signs, especially when they involve negative numbers When solving inequalities involving a modulus sign, be very careful with the inequality symbol. Remember that you need to reverse it if you are multiplying or dividing through by a negative number. Check your answer by substituting a number from within the solution set into the original inequality.
 
Messages
102
Reaction score
4
Points
0
zeebujha said:
Madiha :) said:
can anyone please explain why only -0.5 is the answer ..
The easiest way to understand such problems is to use graphical method
Draw two lines:
y=2-3x
y=|x-3|
You will find that they only intersect at one point: x=-0.5
And |x-3| > 2-3x for all values of x greater than 0.5

No, there is a numerical method. All you have to do is solve for the two answers and check the solution for both of them. One will not fit because the modulus will cancel the negative of one side and so only one solution can be taken.

Reference: J2006 q2
 
Messages
286
Reaction score
228
Points
0
MukeshG93 said:
zeebujha said:
Madiha :) said:
can anyone please explain why only -0.5 is the answer ..
The easiest way to understand such problems is to use graphical method
Draw two lines:
y=2-3x
y=|x-3|
You will find that they only intersect at one point: x=-0.5
And |x-3| > 2-3x for all values of x greater than 0.5

No, there is a numerical method. All you have to do is solve for the two answers and check the solution for both of them. One will not fit because the modulus will cancel the negative of one side and so only one solution can be taken.

Reference: J2006 q2
Buddy, I never said that there was no numerical method to solve the problem. I was just showing the OP what the answers actually meant!
 
Messages
286
Reaction score
228
Points
0
ahmed t said:
zeebujha said:
ahmed t said:
what is the hardest chapter in p3?
the hardest part for me is not getting complacent
yea i guess
they can make a hard question out of the easy chapters so nothin can be easy
yes, all we can hope the examiner was not having a bad day when he was preparing the questions! :D
 
Messages
760
Reaction score
10
Points
0
what i need is a calculator which can intergrate cause i made a silly mistake in p1 intergration but if i had a calculator which could i couldve checked my ans and known i made a mistake
 
Messages
15
Reaction score
0
Points
0
mukesh can u plz solve q-7 of oct nov 2010 variant 31,step wise plz.its the same perpendicular question as u stated above,but those alphabets are confusing me ,can u help me as Asap,or anyone of u can help plz>>>>>
 
Messages
802
Reaction score
290
Points
73
ahmed t said:
what i need is a calculator which can intergrate cause i made a silly mistake in p1 intergration but if i had a calculator which could i couldve checked my ans and known i made a mistake
IT IS NOT ALLOWED BRO :)
 
Messages
760
Reaction score
10
Points
0
man the invigilators here dont care
my friends bring graphics calculators wid em
 
Top