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Mind Blowing function........P1 help

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The function,f(x) is defined for f:x-> 2x^2 -12x + 13 for 0<=x<=A, where A is constant.
i) Express f(x) in the form of a(x+b)^2 + c
ii) State the value of A for which the graph of y=f(x) has a line of symmetry.
iii) When A has the value find the range of f(x).
 
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for the first part its just completing the square.
the second part you want the Y value of A to be the same as the Y value of (when X=0), when X =0 Y=13 now just enter Y=13 in the equetion and find the second value of X which should be 6.
the range will be from the minimum which is C from completing the square and the maximum which is 13
 
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How is this mind blowing? This is a typical P1 Functions question ...
 
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