Paper 3 physics !! get help here :)

[ygyh45]

not really since velocity is speed in a certain direction

 

[Muzammil100]

Hi ! Can you help?

May/June 2011
http://www.xtremepapers.com/papers/CIE/Cambridge%20IGCSE/Physics%20(0625)/0625_s11_qp_31.pdf

Q3)a)i
ii)
iii)
iv)

9)a)i)

 

[ygyh45]

is this variant 1 or 2?

 

[SmartNour]

People I need help please Oct/Nov 2010 p33
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_w10_qp_33.pdf
Q1 a) iii)
Q2 b) i) and ii)

 

[ygyh45]

for 1 a iii : total distance = 100
sbtract distance under area of the first part ( triangle) : 1/2 x 3 x 8 = 12
100 - 12 = 88m this is the total area under graph for the remaingin trapezium (distance)
then area of trapezium (distance = 1/2 (a+b) xh
88 = 1/2 ( 8 + b ( the speed that you r calculating) ) x (14.2 - 3)
then calculate (multiply divide until u find b which is ur answer

 

[SmartNour]

Thank you !! do u know abt the other question ???

 

[ygyh45]

kinda complicated to explain here bt ill try and hope ull get it
in the second picture the pivot is not in mid of P its at the corner and lenght of all P is 0.06 ... now look at the first pic ull see tht distnace is given from mid of P till the end so to calculate the moment at the left ull need fxd f is wat ur calculating and d is distance from half p till the end which is 0.2- (0.06/2) now for the right side u have f which is 160N and distance is again from half P + o.5+ 0.25 now use formula clockwise moment = anti clockwise moment subsitute value and ull get 734N i think check ms
for ii) P add 734 tht u calcuated and 160
all the rest are zero since thy are not in contact

 

[SmartNour]

kinda complicated to explain here bt ill try and hope ull get it
in the second picture the pivot is not in mid of P its at the corner and lenght of all P is 0.06 ... now look at the first pic ull see tht distnace is given from mid of P till the end so to calculate the moment at the left ull need fxd f is wat ur calculating and d is distance from half p till the end which is 0.2- (0.06/2) now for the right side u have f which is 160N and distance is again from half P + o.5+ 0.25 now use formula clockwise moment = anti clockwise moment subsitute value and ull get 734N i think check ms
for ii) P add 734 tht u calcuated and 160
all the rest are zero since thy are not in contact

Thank yoouuuuu sooo muchhhhhh!!!! I finally got itttttt

 

[Muzammil100]

is this variant 1 or 2?

1!

 

[dana xP]

can some body plz explain radioactive dating ??

 

[SmartNour]

can some body plz explain radioactive dating ??

is it even in the syllabus its just a rough idea of how radiactivity is used I dont think we have to know it in detail :S

 

[dana xP]

is it even in the syllabus its just a rough idea of how radiactivity is used I dont think we have to know it in detail :S

r u sure ??

 

[humanlaser]

what conclusion should we write about the nucleas of a gold atom
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s07_qp_3.pdf

ques 11 b

 

[AhmedMans]

http://www.xtremepapers.com/community/threads/need-help-with-this-physics-problem.16445/

Help please