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Paper 3 physics !! get help here :)

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for 1 a iii : total distance = 100
sbtract distance under area of the first part ( triangle) : 1/2 x 3 x 8 = 12
100 - 12 = 88m this is the total area under graph for the remaingin trapezium (distance)
then area of trapezium (distance = 1/2 (a+b) xh
88 = 1/2 ( 8 + b ( the speed that you r calculating) ) x (14.2 - 3)
then calculate (multiply divide until u find b which is ur answer
 
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kinda complicated to explain here bt ill try and hope ull get it
in the second picture the pivot is not in mid of P its at the corner and lenght of all P is 0.06 ... now look at the first pic ull see tht distnace is given from mid of P till the end so to calculate the moment at the left ull need fxd f is wat ur calculating and d is distance from half p till the end which is 0.2- (0.06/2) now for the right side u have f which is 160N and distance is again from half P + o.5+ 0.25 now use formula clockwise moment = anti clockwise moment subsitute value and ull get 734N i think check ms
for ii) P add 734 tht u calcuated and 160
all the rest are zero since thy are not in contact
 
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kinda complicated to explain here bt ill try and hope ull get it
in the second picture the pivot is not in mid of P its at the corner and lenght of all P is 0.06 ... now look at the first pic ull see tht distnace is given from mid of P till the end so to calculate the moment at the left ull need fxd f is wat ur calculating and d is distance from half p till the end which is 0.2- (0.06/2) now for the right side u have f which is 160N and distance is again from half P + o.5+ 0.25 now use formula clockwise moment = anti clockwise moment subsitute value and ull get 734N i think check ms
for ii) P add 734 tht u calcuated and 160
all the rest are zero since thy are not in contact
Thank yoouuuuu sooo muchhhhhh!!!! :D I finally got itttttt
 
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