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Paper 5 Tips !! :)

K

Kinjal

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xhizors said:
Their would be to lines one at higher temperatures (solubility temperature) and the other at lower temperature (crystals appearing)
on x-axis Temperatures and on Y-axis Solubility
u extend both of these lines and the point of intersection is their transition temperature!
Click to expand...

Yeah exactly,i did get two curves and when i checked with the marking scheme, it says that the first line (at lower temp) has a steeper gradient and vice versa while i got the oppposite. Is the transition temp around 49C?? Plus all my solubilities were above 100! Is that corrct??
 
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stella jazz

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when they ask us to calculate solubility and say :
"The units of solubility are grams per one hundred grams of water (g / 100g water)." What does this mean???? and what formula do we use?
thanx in advance
 
iKhaled

iKhaled

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stella jazz said:
when they ask us to calculate solubility and say :
"The units of solubility are grams per one hundred grams of water (g / 100g water)." What does this mean???? and what formula do we use?
thanx in advance
Click to expand...
the unit means how many grams of the "solute" dissolves (soluble) in 100g of water
 
xxfarhaxx

xxfarhaxx

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Kinjal said:
Yeah exactly,i did get two curves and when i checked with the marking scheme, it says that the first line (at lower temp) has a steeper gradient and vice versa while i got the oppposite. Is the transition temp around 49C?? Plus all my solubilities were above 100! Is that corrct??
Click to expand...
this is my graph.. u rely havin troubl wit tat qustn ha..hope it hlps!!
 

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SalmanslK

SalmanslK

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MJ 2011 52 can any one check if my solution is correct?

image.jpg



image.jpg


image.jpg
 
K

Kinjal

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xxfarhaxx said:
this is my graph.. u rely havin troubl wit tat qustn ha..hope it hlps!!
Click to expand...
Omg,thankyou soo much!!! Turns out my coordinates were correct,i just drew curves instead of lines! :/
Yes,i was really stressed out after doing this qn! Really helped! Thanks again! :)
 
ghlamo

ghlamo

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is t
xhizors said:
Expt has to be commenced on a given temp say 30*C for expt 1
u set the temp of a water bath
u place the conical flask in water with mixture u measure temp and start stopwatch when 30*C hits
at this point temp of water in bath = mixture of solution in flask as they are in equilibrium (zeroth law)
if u start stopwatch before 30*C hits u measure rate for x-30*C
now tell me which part is unclear!
Click to expand...
is thermometer to be placed in water bath or conical flask
 
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