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Guys did anyone put condensation for the process
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I guess I'm wrong in this one too -_-
They had to add up to 8V I think
It
It was C
Who knows? I could be wrong, but the resistor HAS to get some P.D. cause it does have resistance.
I got B for the ball one. Anyone else?
Um how is ig p4 and physics p1 even related lolGuys no need to worry about this paper at all, if you do good in papers 2 n 3 you still end up with an A cuz they take the avg of the papers ( I have a friend who messed up like 30/120 marks in IG Maths p4 and still ended up with A*)
I put evaporationGuys did anyone put condensation for the process
The first voltage was of the first resistorWho knows? I could be wrong, but the resistor HAS to get some P.D. cause it does have resistance.
I got B for the ball one. Anyone else?
Q was BI remember it was q I guess do you which option was that?
Sorry it was R I suck at memorizing things:/ I calculated that like 2 times and it was RQ was BBecause they put options P, Q, R and (D) was none of these, I think. Q was the one with 2.0 m/s right?
THANK U! It wasn't r btw it was s r wasn't even an option lolSorry it was R I suck at memorizing things:/ I calculated that like 2 times and it was R
Yup me. Wait didnt the resistances add up to 8V when the PDs were 3V and 2V...the last resistor also had to be 3V and 3+3+2=8V no?Who knows? I could be wrong, but the resistor HAS to get some P.D. cause it does have resistance.
I got B for the ball one. Anyone else?
I didn't understand that question at all...I think I marked the 800 oneI don't remember the question exactly, but what did you put for the potential divider question where we had to find the resistance of the resistor? Options were like 755, 855, 955 and 1055 I think
Yes, however there was also a resistor, so that takes up P.D. as well. And if one resistor in parallel already has a P.D. of 1 V then how will the others have 3? Voltage is the same in parallel.Yup me. Wait didnt the resistances add up to 8V when the PDs were 3V and 2V...the last resistor also had to be 3V and 3+3+2=8V no?
Yup that's my point but I don't even remember the question exactlyYup me. Wait didnt the resistances add up to 8V when the PDs were 3V and 2V...the last resistor also had to be 3V and 3+3+2=8V no?
I did 795 or something like thatI don't remember the question exactly, but what did you put for the potential divider question where we had to find the resistance of the resistor? Options were like 755, 855, 955 and 1055 I think
Yup, I guessed the same as well *high five*I didn't understand that question at all...I think I marked the 800 one
options but I rmr first one was 395 and second was 795 I calculated it to be 795 so I chose BI don't remember the question exactly, but what did you put for the potential divider question where we had to find the resistance of the resistor? Options were like 755, 855, 955 and 1055 I think
Wait wait gain in kinetic energy was equal to the loss in potential energy...and it lost 1/4th of its potential energy when it gained 1/4th of its kinetic energy so .5*4*4=8 and 1/4th of that is 2J which is equal to .5*2*2 so that's why I marked BSorry it was R I suck at memorizing things:/ I calculated that like 2 times and it was R
The one in parallel had 1V and there was another with the same with series with it so it also was 1V. Total 2V and parallel to them would be 2V too. I don't remember how many more resistors there wereYes, however there was also a resistor, so that takes up P.D. as well. And if one resistor in parallel already has a P.D. of 1 V then how will the others have 3? Voltage is the same in parallel.
I calculated 800 so just wrote 795I don't think those were the
options but I rmr first one was 395 and second was 795 I calculated it to be 795 so I chose B
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