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How were we supposed to calculate power?
P= Current square x Resistance of two wires.
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How were we supposed to calculate power?
I used the same formula.. but how two wires? How do we know that there are two wires? I simply used I^2 x resistance of one wire, will I get any mark?P= Current square x Resistance of two wires.
there were two wires, From the two terminals of the battery.I used the same formula.. but how two wires? How do we know that there are two wires? I simply used I^2 x resistance of one wire, will I get any mark?
gt will be around 37
how was it?wt do u expect the GT ?wasnt it hard than may june?
39 was A and 35 was B.what was the gt in may june 2013??
How did you calculate it? I wrote 5 mm.yooo guys wat was the amplitude...???
39 was A and 35 was B.
Just search on google.. you'll get it.can u send me the link to the gt?
How did you find intensity? K value? I think we should relax and focus on paper 1 now.. I made A lot of mistakes. I hope percentile will save all us. Gt should be 35how did ya know it was 5mm...??nd i dont think dat we had a calculation cuz it was jst 1 mark...i took frequency nd calculated Intensity nd with the relation I=ka^2 calculated amplitude...dont remember the ans...
yes..btw what was your distance in the cro question? mine was 360 :/did anyone get power=41w and pq =.18m
for the formula you will get 1.I used the same formula.. but how two wires? How do we know that there are two wires? I simply used I^2 x resistance of one wire, will I get any mark?
Wow!! You were able to solve 2nd questionyes..btw what was your distance in the cro question? mine was 360 :/
yes..btw what was your distance in the cro question? mine was 360 :/
yes though the answers different for everyone.Wow!! You were able to solve 2nd question
How did you calculate it? I wrote 5 mm.
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