Wow!! You were able to solve 2nd question
mine was comming in thousands
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Wow!! You were able to solve 2nd question
What do you think of gt this time?mine was comming in thousands
no 39 was A nd 33 was B39 was A and 35 was B.
its actually 20mmi think it was 40mm
How did you get 20mm?its actually 20mm
Two forces were normal contact force and weight? And how did you draw the wave?I got 120 m in question number 2 what did you people get? i got 0.19 or 0.18 in pq distance
Amplitude was 40 mm. A travelled a total distance of 80 mm from extreme down to the top. So amplitude is the greatest distance travelled from mean position. Dividing 80 with 2 gives 40. So, it's 40yooo guys wat was the amplitude...???
Two forces were normal contact force and weight? And how did you draw the wave?
Stationary wave is formed when identical waves overlap blah blah... I wrote progressive and transverse.. no? I drew the wave in same manner..0.05 was i/4 th a wave since it's a stationary wave i drew a flat line :/ don't know if it's right
Stationary wave is formed when identical waves overlap blah blah... I wrote progressive and transverse.. no? I drew the wave in same manner..
did anyone get power=41w and pq =.18m
Stationary wave is formed when identical waves overlap blah blah... I wrote progressive and transverse.. no? I drew the wave in same manner..
How were we supposed to calculate power?
P= Current square x Resistance of two wires.
Exactly, the threshold should be like 56/57 on 60 for an A
WELL, I don't know.. I thought stationary wave is only produced when two identical wave overlap while passing through same medium at the sane time in exactly opposite direction..and in stationary wave, all particles oscillate with same amplitude, right? Anyway, it was transverse right?I also wrote stationary since they said it was UNDER TENSION and they also showed that at the end it was like a straight line.. What do you guys think?
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