- Messages
- 45
- Reaction score
- 4
- Points
- 18
But can it be air resistance?
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what were the 3 points for the alpha beta particle question
1 was because of mass
2 cause of charge
what was the 3rd 1?
did anyone get power=41w and pq =.18m
45??? Impossible.. it would be in 30's...the gt would be 42-45
Wave was progressive and transverse? Want to confirm again..the gt would be 42-45
Wave was progressive and transverse? Want to confirm again..
Time period was given so I calculated frequency.. then I used this formula v=fx wavelengthexactly and the speed for the wave?
Time period was given so I calculated frequency.. then I used this formula v=fx wavelength
how were we supposed to find the distance PQ? and what about the graph that was to be made in the other part? was it a curve or a straight line??
I wrote progressive and transverse too since the wave was travelling on the rope. And according to me the question was meant to point that travelling wave and not the one which would be formed by the superposition of incident and the reflected wave.
Exactly, the threshold should be like 56/57 on 60 for an A
find the deceleration by 14/0.4=-35 and then distance by 2as=v2-u2 where u was 2.4ms the line was a straight line
I did the same what was your speed for the wave
its progressive as direction of travel was horizontal..and transverse yes.WELL, I don't know.. I thought stationary wave is only produced when two identical wave overlap while passing through same medium at the sane time in exactly opposite direction..and in stationary wave, all particles oscillate with same amplitude, right? Anyway, it was transverse right?
no way bro..maximum students left no. 2 untouched..so there goes 7 marks..how do you expect it to be more than 35?the gt would be 42-45
SameI did the same it was 1 osc in 0.2 sec so in one sec it would be 5 as frequency was 5hz and wavelength 1.5m the speed i got was 7.5ms and u
Are you sure we were supposed to calculate using equation of motion?? I used equation of motion too to calculate ow distance... But most of the ppl calculated it by using formula work done= force x distance.. work done was there, taking force value from the graph.. and they are getting 0.081.. I think we did it wrong.. we were not supposed to calculate pa using equation of motion..find the deceleration by 14/0.4=-35 and then distance by 2as=v2-u2 where u was 2.4ms the line was a straight line
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