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physics and chemistry doubts!!

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3 N-H bonds which are twice as mentioned in eq.
2x3=6
6x388= +2328
H-H is breaking so endo, nd N-H is forming so exo..
energy taken in for bond breaking is (944+1308=2252), while energy released in bond making is 2328..
energy released in bond making is more than energy taken in for bond breaking so forward reaction is exo..
thaaanks alot! really helped :)
 
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@dupi2bro how do u take a snapshot of your screen? i try that on my laptop but it doesn't work..:(
 
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moles of oxygen=0.08dm/24=3.33x10-3
2 moles of oxygen react with one mole of methane so cross multiplication
(3.33x10-3 x 1)/2 = 1.67x10-3 mol of methane
now find volume of methane from volume=mole x 24
v= 1.67x10-3 x 24 = 0.040 dm
convert dm in cm
0.040x1000= 40 cm
now find percentage in 60 cm sample...
40/60 x 100 = 66.67 %
(note with all cm nd dm they are cubic)
hope u get it nd plzz ask if any doubt..:)(y)
 
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How to solve:

20 cm^3 of a hydrocarbon was burnt in 175 cm^3 of oxygen. After cooling, the volume of the remaining gases was 125 cm^3. The addition of aqueous sodium hydroxide removed carbon dioxide leaving 25 cm^3 of unreacted oxygen.


iii) Deduce the formula of the hydrocarbon and the balanced equation for the reaction.

Why does it say in the mark scheme that any combustion equation of an ALKENE would do? Why not an alkane?

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Chemistry (0620)/0620_s13_qp_33.pdf
 
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