Physics, Chemistry and Biology: Post your doubts here!

[ThatReallyReallyWeirdDude]

Never learned how to calibrate a C.R.O , only thermometers .
If thats a question from a past paper in around 2000-2005, the syllabus was a little different back then.

Yeah I guess, i just checked syllabus, calibration not there (this is the bit where we all fall to the floor and thank Allah)

 

[tribianni]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s04_qp_3.pdf Q4 a
nd State what is meant by the terms analogue and digital

 

[Muzammil100]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s04_qp_3.pdf Q4 a
nd State what is meant by the terms analogue and digital

Look above! For the analogue digital! I dont know!

 

[Muzammil100]

Can someone help!

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_w11_qp_33.pdf

Q)3)b)
Q)8)a) & c)

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_w11_qp_32.pdf

Q)5)b)

http://www.xtremepapers.com/papers/CIE/Cambridge%20IGCSE/Physics%20(0625)/0625_s11_qp_31.pdf

9)a)i)

 

[EpicLol]

ho
w

0.5m/s^2 is acceleration due to 0.4N but as it was said before since it starts from rest, it is average which is 0.25m/s^2 so we divide 0.25*1.2 and then *1.2 the answer again.....
hope that helps

 

[EpicLol]

Can someone help!

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_w11_qp_33.pdf

Q)3)b)
Q)8)a) & c)

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_w11_qp_32.pdf

Q)5)b)

http://www.xtremepapers.com/papers/CIE/Cambridge%20IGCSE/Physics%20(0625)/0625_s11_qp_31.pdf

9)a)i)

For 9)a)i) Its downwards and for a)ii) its anti clockwise....as if u use the flemmings left hand rule or just the right hand rule you can find the direction of the force produced by the interaction of the electric current and the magnetic feild.

 

[aliiiiiiiiii]

v=u+at?
u= initial speed, acceleration = a=0.5 t=1.2
v=0 + 0.5(1.2) =0.6m/s
ii) Distance
can use average speed (s= [v+u]/2 * t]
which gives distance = 0.3*1.2=0.36
or s=ut+1/2at^2
=0+(0.5)(0.5)(1.2)^2=0.25*1.44=0.36

y we dont use the formula speed=distance/time
it will be 0.6*1.2

 

[aliiiiiiiiii]

0.5m/s^2 is acceleration due to 0.4N but as it was said before since it starts from rest, it is average which is 0.25m/s^2 so we divide 0.25*1.2 and then *1.2 the answer again.....
hope that helps

y we dont use the formula speed=distance/time
it will be 0.6*1.2

 

[EpicLol]

because u need the acceleration for getting the answer not just the speed and distance

y we dont use the formula speed=distance/time
it will be 0.6*1.2

 

[aliiiiiiiiii]

because u need the acceleration for getting the answer not just the speed and distance

thanx

 

[aliiiiiiiiii]

v=u+at?
u= initial speed, acceleration = a=0.5 t=1.2
v=0 + 0.5(1.2) =0.6m/s
ii) Distance
can use average speed (s= [v+u]/2 * t]
which gives distance = 0.3*1.2=0.36
or s=ut+1/2at^2
=0+(0.5)(0.5)(1.2)^2=0.25*1.44=0.36

thanx

 

[Stormcry72]

just finished physics paper 3 variant 2

 

[fatima360]

how did the paper go??

 

[Stormcry72]

how did the paper go??

it was long as anything, and tricky too
but i'm not going to discuss any questions though

 

[areeba fatima]

WITH air resistance, it's acceleration isn't known..
WITHOUT air resistance, you can straight away tell that it accelerates at 10m/s because the force of gravity is 10 m/s

Thank you soo mcuh

 

[areeba fatima]

Without air resistance, it falls at a constant acceleration.
With air resistance, it accelerates at the bigining until air risitance is equal to the object's weight, causing a resultant foce of zero, it'll start falling at a terminal speed (constant speed) <--- After it accelerates in the begining

Thank you

 

[areeba fatima]

Alright then
When any object is falling the main thing acting on it will be the weight of the object, pulling it downwards. As per Newton's second law this will cause acceleration.
When there's no air resistance the acceleration will be constant, as nothing is opposing it (this means the graph of the speed will be a straight line)
When there IS air resistance, the air resistance will act in the opposite direction as the weight, so the net force = weight-air resistance
As the speed of the object increases, so does the air resistance until the point where weight = air resistance, so net force = 0
As per newton's FIRST law, it will have a constant speed (when no force is acting on an object it will eithe rmove with a steady speed or not move etc.)
So acceleration will decrease until it is zero and speed is constant, and this speed is called the terminal velocity
The graph will be a curve where the gradient decreases until it becomes straight

thank you so much for a detailed answer!

 

[Zein96]

just finished physics paper 3 variant 2

How was it ?

 

[rock1996]

what happens if in o level physics exam p2 three questions are done in section B instead of 2

 

[kainat husain]

how did the paper go??

some were really bad questions! did u write?