Physics, Chemistry and Biology: Post your doubts here!

[chaotic]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_w10_qp_33.pdf

Please need help in question 10, all of it.

 

[Yousif Mukkhtar]

well yes that's ok i am just askin what is peak to peak height? is it for x plates or y?

I guess peak to peak height is amplitude. It is controlled by the y-plates.

 

[kainat husain]

I guess peak to peak height is amplitude. It is controlled by the y-plates.

ahan thnx

 

[kainat husain]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s10_qp_32.pdf 10 a and b

hey can u answer this?0625/31/m/j/08
q- 9 a. how can we draw magnetic fields like what rule should we follow and c (ii) how do we knw it will move towards the thick wire?

 

[EpicLol]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_w10_qp_33.pdf

Please need help in question 10, all of it.

Im not sure of part a but for part b look at the image....but the lines have to be straight and drawn with a ruler

 

[EpicLol]

hey can u answer this?0625/31/m/j/08
q- 9 a. how can we draw magnetic fields like what rule should we follow and c (ii) how do we knw it will move towards the thick wire?

could you please provide a link to the question paper?
Thx

 

[AAnsarii]

Sorry but no I'm fine with answering questions but don't have time to do what you ask for. Sorry!

A stream of beta particles is like current (it's a line of moving electrons in the end)
So to know the change in direction you use fleming's left hand rule
just remember that since the beta particles are a stream of electrons, you have to use it backwards since conventional current is opposite to flow of electrons.
I.e. if beta particles are going to the right, you should point your second finger to left.

Thanks

 

[kainat husain]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_w10_qp_33.pdf

Please need help in question 10, all of it.

part a has done by some one perfectly u can chck in previous pages

 

[justforinformation]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s10_qp_31.pdf question 11 b pl0x.

 

[ThatReallyReallyWeirdDude]

ALRIGHT THEN!
*bang head against desk*
TIME BASE
The time base effects the frequency of the shown wave!
If the time base is 1 second, then it will show the number of waves in 1 second!
If time base is 0.5 seconds it will show the number of waves in 0.5 seconds!
So the smaller the time base the less number of waves which appear/the wider they are. If you had LOTS of waves and they were all squashed, you would decrease time base to make it clearer. This also means decreasing time base INCREASES wavelength of shown wave.
If it says time base is 5seconds/cm, it means that each cm represents 5 seconds. So if they ask to find the frequency from this this is what you do:
Find the number of centimeters/blocks for one wave (e.g. 5cm)
Multiply this by the time base (e.g if time base is 0.01second/cm, then that's 0.05cm)
This is the PERIOD the time taken for ONE wave
Frequency = 1/Period, so the frequency is 1/0.05 = 20Hz!
Y-GAIN
The Y-Gain effects the HEIGHT of the shown wave.
The height of the wave shows the voltage of the wave
So if the Y-Gain is 5volts/cm and the amplitude of the wave on the screen is 4cm, then the voltage of the wave is 5*4=20V!

 

[kainat husain]

could you please provide a link to the question paper?
Thx

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s08_qp_3.pdf

 

[chaotic]

Im not sure of part a but for part b look at the image....but the lines have to be straight and drawn with a ruler

Thank you

part a has done by some one perfectly u can chck in previous pages

There is 65 pages

 

[chaotic]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_w10_qp_32.pdf
2b (i) and (ii)

Need help, the answer in the mark scheme is confusing.

 

[ThatReallyReallyWeirdDude]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s10_qp_31.pdf question 7 b pl0x.

b)i) 4 minutes (because this is when the difference between sight/sound is smallest)
ii)Because the difference between hearing/seeing was never 0 seconds (because the scientists aren't dead is unfortunately not a correct answer. D
iii) Speed = Distance/Time = 1200/3.6=333.33m/s
iv) The assumption is that light reaches the scientists instantaneously

 

[kainat husain]

ALRIGHT THEN!
*bang head against desk*
TIME BASE
The time base effects the frequency of the shown wave!
If the time base is 1 second, then it will show the number of waves in 1 second!
If time base is 0.5 seconds it will show the number of waves in 0.5 seconds!
So the smaller the time base the less number of waves which appear/the wider they are. If you had LOTS of waves and they were all squashed, you would increase time base to make it clearer. This also means decreasing time base INCREASES wavelength of shown wave.
If it says time base is 5seconds/cm, it means that each cm represents 5 seconds. So if they ask to find the frequency from this this is what you do:
Find the number of centimeters/blocks for one wave (e.g. 5cm)
Multiply this by the time base (e.g if time base is 0.01second/cm, then that's 0.05cm)
This is the PERIOD the time taken for ONE wave
Frequency = 1/Period, so the frequency is 1/0.05 = 20Hz!
Y-GAIN
The Y-Gain effects the HEIGHT of the shown wave.
The height of the wave shows the voltage of the wave
So if the Y-Gain is 5volts/cm and the amplitude of the wave on the screen is 4cm, then the voltage of the wave is 5*4=20V!

thnx it really helped! can u please show how to draw this one plsss
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s10_qp_32.pdf
10 a

 

[ThatReallyReallyWeirdDude]

ahan thnx

PEAK TO PEAK HEIGHT IS THE HEIGHT DIFFERENCE BETWEEN CRESTS AND TROUGHS!
SO IT'S TWO TIMES THE ALTITUDE!
*facepalm*

 

[justforinformation]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s10_qp_31.pdf is it just everyone ignoring me or no1 can actually answer it?

 

[Stormcry72]

hey can u answer this?0625/31/m/j/08
q- 9 a. how can we draw magnetic fields like what rule should we follow and c (ii) how do we knw it will move towards the thick wire?

use the right hand grip rule with the thumb pointing in direction of the current, the fingers will show the direction of the magnetic field
for cii) since the magnetic field is clockwise for both wires, they cut each other in opposite directions hence they are attracted to each other

 

[thats_me]

Thank you


There is 65 pages

even em lookin for it if u find do tell me the page no.

 

[EpicLol]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Physics (0625)/0625_s10_qp_31.pdf question 7 b pl0x.

i) 4.0 as the least difference = closest to person....
ii) because there was time difference between lightning and thunder....
iii) 1200/3.6 = 333.3....m/s
iv) 330m/s