Physics MCQs thread.

[mrpaudel]

for 27..its D...defn of Electric field strength

 

[cocospaniel]

http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_w09_qp_11.pdf
Q.19 nd Q.30 plzzz

Q19 - Pressure= P(density)hg
Rearranging
density= 15200/(80*10^-2)*(10) = 1900 so it's B

Q30- It's A.

 

[histephenson007]

http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_w09_qp_11.pdf
Q.19 nd Q.30 plzzz

For question no. 19,
Pressure = 15200
Pressure = F / A

Therefore, F = P * A
(the only force here is the weight)

W = P * A
mg = P*A
therefore,
m = (P*A)/g
= (15200/9.81) A
m = 1550 A

Since it is rectangular,
Volume = A * h

Therefore density = m/V
= 1550 A / Ah
(cancel the A)

=1550 / h

u'll get the answer

 

[mrpaudel]

Hi, can anyone please do questions number 5, 9, 13, 18, 22, 34 and 36? Thanks a lot =)

http://www.xtremepapers.me/CIE/Internat ... _qp_11.pdf

for 36..its B...the three resistance in the right are in series..as a current passes through the 1st passes through other two..so it gives u total of 30ohm ...which is now parallel to 10ohm..so its combine resistance is 7.5 thus B!

 

[histephenson007]

LOL... I totally forgot the pgh equation T.T

 

[mrpaudel]

for 9..its C...first use v^2-u^2=2as where V=0 and u remains u and S=x and a shud b calculated..and from that we get a= -u^2/2x....
now question says no change in deceleration...so using that formula again...v^2-u^2=2as where v=0 again..and u1=1.2u(since the speed in increased by 20%)...and s needs to b calculated..

so 0-1.44u^2=2(-u^2/2x)* s...which gives s=1.44x..thus C

 

[cocospaniel]

Nov 2008, Q 27?

 

[mrpaudel]

for 22..we can use unitary method bcoz this xtension and force has linear relation...so for 3m of x= extension is 1.5mm...therefore for 1m of x= extension is 0.5mm..
Similarly, for y 1m=1mm..so 3m=3mm..total extension, therefore, is =3mm+0.5mm=3.5mm!!

 

[mrpaudel]

@cocospaniel: sorry dude, from my side ..i cannot help u,...i dont have any idea( for varient 12) if u are talking other varient..let me know..will try!!

 

[histephenson007]

Nov 2008, Q 27?

The wavelength is 15 mm
Speed (of light ) is 3*10^8
u just need to calculate for the frequency..

 

[mrpaudel]

@nerd07: for 34....u use wire of length 800m..therefore has resistance of 800*0.005=4ohm...so minimun e.m.f=V+Ir=16+(0.6*4)=18.4V thus C.!! i dont know rest of the questions!!

 

[Xthegreat]

Nov 2008, Q 27?

Q27.
all electromagnetic waves travel at the speed of light = 3 x 10^8
- microwaves = electromagnetic wave
- wavelength = 2 x 15 = 30mm ( *try drawing out the stationary wave, maximum is the Antinode )
- using v= freq x wavelength
- just apply the formula, you will get C

 

[kirashinagami]

how bout this one comrade?

 

[Mueez]

Hi, can anyone please do questions number 5, 9, 13, 18, 22, 34 and 36? Thanks a lot =)

http://www.xtremepapers.me/CIE/Internat ... _qp_11.pdf

for Q.18
as u knw rate of energy conversion=power nd also p=fv
power required to lift m1 = power given by falling of m2 + power by motor
m1gv = m2gv + power by motor

 

[rabib2013]

i did get it right, but couldn't understand it with clarity. :\

 

[sniper7137]

Hi. Can anyone explain Q12 and Q26 of October November 2009 variant 1? And Q15 and Q23 of May June 2009?

 

[Mobeen]

http://www.xtremepapers.me/CIE/index.ph ... _qp_12.pdf
qs 13,14.26 help.... plzzzzzz

 

[arlery]

Hi. Can anyone explain Q12 and Q26 of October November 2009 variant 1? And Q15 and Q23 of May June 2009?

Q12,November 2009 variant 1

Since the picture is same, hence no change in mass, so R1 = R2

Now look closely, T1 is closer to picture then T2, so more force will be required. Therefore, T1>T2

B

 

[mrpaudel]

i did get it right, but couldn't understand it with clarity. :\

its C..its so simple...1 and 4 involves units...whereas number 2 is wrong..so its obv that its C..!!

 

[nerd007]

@nerd07: for 34....u use wire of length 800m..therefore has resistance of 800*0.005=4ohm...so minimun e.m.f=V+Ir=16+(0.6*4)=18.4V thus C.!! i dont know rest of the questions!!

Thanks for taking out the time to solve my questions. Anyone know how to do 5? looks like a tough one.