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It's D.
Take 10 percent of pressure. p0=P(density)hg * 1/10
you will get p0=Phg/10. Then make the height the subject of the formula
so h=10P0/pg
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DeathDealer said:
If motion is perp to acc consider a particle launched horizontally in the air. The perp acc is g acting on it. So it's horizontal speed will remain constant (a fact) wheras it's direction will change due to the downward force acting on it.DeathDealer said:
DeathDealer said:http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_s08_qp_1.pdf
Azwel az Ques 24
cocospaniel said:
It's D.
Take 10 percent of pressure. p0=P(density)hg * 1/10
you will get p0=Phg/10. Then make the height the subject of the formula
so h=10P0/pg![]()
ninjas4life said:cocospaniel said:
It's D.
Take 10 percent of pressure. p0=P(density)hg * 1/10
you will get p0=Phg/10. Then make the height the subject of the formula
so h=10P0/pg![]()
but the answer in the mark scheme is a...
DeathDealer said:http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_s09_qp_1.pdf
Ques 15
Mueez said:http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_s10_qp_11.pdf
Q.16 nd Q.22 plzz
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