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Physics MCQs thread.

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It's D.
Take 10 percent of pressure. p0=P(density)hg * 1/10
you will get p0=Phg/10. Then make the height the subject of the formula
so h=10P0/pg :)
 
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DeathDealer said:
http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_s08_qp_1.pdf

Azwel az Ques 24

It's C aswell becuase the question said they are the same type of wires therefore the young modulus is the same for both. :)
 
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cocospaniel said:

It's D.
Take 10 percent of pressure. p0=P(density)hg * 1/10
you will get p0=Phg/10. Then make the height the subject of the formula
so h=10P0/pg :)

but the answer in the mark scheme is a...
 
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ninjas4life said:
cocospaniel said:

It's D.
Take 10 percent of pressure. p0=P(density)hg * 1/10
you will get p0=Phg/10. Then make the height the subject of the formula
so h=10P0/pg :)

but the answer in the mark scheme is a...

My bad, I meant to multiply by 10, then rearrange the formula and you'll get h=P0/10pg. Thanks for pointing that out :Rose:
 
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DeathDealer said:
http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_s09_qp_1.pdf

Ques 15

It's B
Potential energy = mgh.
When both vessels are equal, h becomes 1/2, m becomes 1/2, g stays the same.

So Potential energy = h/2 * m/2 * g and you'll get mgh/4
 
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Mueez said:
http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_s10_qp_11.pdf
Q.16 nd Q.22 plzz

Q16. It's D, Work Done = Fd.. So efficiency is input/output. therefore mgsi(theta)d/Fd, you cancel d. It's hard to explain this over internet but I hope this help. :)




Q22. It's C, this website will help you, it has the frequencies and wavelengths for waves http://en.wikibooks.org/wiki/A-level_Ph ... _a_wave%3F
 
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