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Physics MCQs thread.

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kirashinagami said:
urgent help before i sleep!
The total work done is the area under the graph.
you can divide the graph into 2 parts : the triangle and the trapezoid
then u just do some basic math...
 
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kirashinagami said:
urgent help before i sleep!


Area of triangle is 0.5 x 500 x 10 x 10^-3
=2.5

Area of trapezium is 0.5 x (500 + 550) x 2 x 10^-3)
=1.05

Add them both and you get 3.55 J
 
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ambitious1 said:
May/June 2009 01 Q. 14 & 15 pleaasee :)

14 - Power = Work Done / Time taken (work done = Fd)
P= Fd/t (d/t=v)
P=Fv (F=kv^2) Therefore P= kv^2 * v = kv^3
So Rearraging k= P/v^3


15 - Potential energy = mgh. When PE is equal for both, h is halved and mass is halved. g is constant.

so PE= m/2 * h/2 * g = mgh/4 :)
 
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histephenson007 said:
DeathDealer said:
http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_w09_qp_11.pdf

Ques 27 wd REASON ?
Any1 !
help plzzz...

because in E = F/Q we always use the charge of the particle 1.6 x 10^-19
 
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arlery said:
histephenson007 said:
DeathDealer said:
http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_w09_qp_11.pdf

Ques 27 wd REASON ?
Any1 !
help plzzz...

It will be A because since both particles are deflected downwards, it means that they are attracted towards plate Q. Since negatively charged particles are attracted towards positive plates. Hence it is A.
I don't get it...
 
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Octahedral said:
Please can someone EXPLAIN this?

Since all the wires are in parallel. So (6 x 1/10) +1/100
= 1.6 ohms This is arlery who worte this, I just copied and pasted it.
 
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@histephenson007


I'm sorry I explained the wrong question, I've edited the post now.
 
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DeathDealer said:
http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_w09_qp_11.pdf

Q : 17

It's C, kinetic energy is the same. Potential energy is not. So it can't be A, or B or D.
 
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