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I think my exam went well. I have my doubts about the p.d. across CD and the power 60W question. I'm also hearing that the threshold will probably be around 43-45. Lets start discussing now shall we?
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isnt the resistor voltage also 12v since it is parallel so both wires have 12v from the power supply. so i said (x/0.4) =(12/1) to give x to be 4.8v. this was the potentiometer formula. if u use proptions u also get 4.2v since the current in the wire was 1.2A.yeah p.d and I1 both 3.2.
R=L/A so we can find resistance for 40cm long wire. We are given 10 ohm resistance for 1m so we can calculate the resistance for 40 cm long wire by using unitary method.
Across 4 ohm resistor voltage was 8 V. So 8-4.8 gives 3.2 V which is the required answer.
Yes gamma I wrote it too what was the next question regarding it ?And guys which radiation emits in last question.....is it gamma ???
i got 0.6what the ratio b/w power dissipated was it 2:5
3/5 since power in wire was 14.4 and power in resistors total was 24. 14.4/24=0.6=3/5ratio was either 3:5 or 5:3 ..... i think... what was correct one?
yes i got 0.6 also.3/5 since power in wire was 14.4 and power in resistors total was 24. 14.4/24=0.6=3/5
correctwhat was the Force in the string when it was released I wrote TENSION
rightyes i got 0.6 also.
Solids -regularly arranged closely packed
Polymer-Long chain of small molecules know as monomers
amorphous- irregularly arranged not closely packed
Is this Okay ?[/quabsolutely correctSolids -regularly arranged closely packed
Polymer-Long chain of small molecules know as monomers
amorphous- irregularly arranged not closely packed
Is this Okay ?
potentiometer formula cannot be used because potentiometer is the device which is used to compare between emfs. Since there is 12V emf, potentiometer formula cannot be used in my opinion.isnt the resistor voltage also 12v since it is parallel so both wires have 12v from the power supply. so i said (x/0.4) =(12/1) to give x to be 4.8v. this was the potentiometer formula. if u use proptions u also get 4.2v since the current in the wire was 1.2A.
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