- Messages
- 18
- Reaction score
- 0
- Points
- 11
rviboy said:uable to solve a part. don't have a convincing answer for that
b) Electric field strength = Potential difference / distance between the plates. equate the values get the answer...
c) electric field strength = Force / charge so F here is equal to mg , equate both equations Eq = mg ..equate the values.
if u dnt get anything u can ask me !
Well I cant understand the question u are asking plz locate me to the paper and question number...