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but i think our minima should be any point between 33 and 8.25. Remember where we said path difference and we said (n+0.5) x(lamda) right? Replace that n with any number starting from 1 alright, and equate that to your path difference (first it would be (1.5)(lamda) = 28) find lamda for each, now after that replace n with 2 then with 3 then with 4 and find lamda for each, now count how many of your lamdas that you found are between 33 and 8.25 (the two values we calculated before, you should get 2 values, that is the number of minima! But im not so sure if im right, but it seems like its right 
, it was, initially.. )
thanks a lot ! i appreciate itFor 4b you should just think of the springs as resistors (like resistors in parallel and in series) the two springs in the first box of the question are in series and the two springs in the second box are in parallel. Now in series, you can say (just like how you find total resistance of 2 resistors in series) the extension is e + e = 2e (if you want to take it as resistors then you can say that resistance of each is e, so total resistance would be 2e). Its the same for all of them, just take them as resistors. Now to find k for each, you just use the equation F=kx, and use the respective extensions that you have calculated for each arrangement.
For number 5 it was a real challenge, especially part (b), but i think i got it (not sure if i am right though), i dont think i need to explain (a) right? Ok so part be, first calculate path difference, to do this first find the distance S2M (distance from S2 to M) using Pythagoras, then the path difference would be S2M - S1M = 128 - 100 = 28 (path difference is basically the difference that each wave has to travel, as the wave from S1 only travels 100 cm and wave from S2 travels 128 cm). Now for the intensity of sound to be 0 (a minima) the path difference should be (n +0.5)(lamda). So we have the speed (330) and 2 frequencies (1 kHz and 4kHz) so calculate 2 values of lamda using both these 2 frequencies, you will get 33 cm and 8.25 cm. Now after this part i am a bit less sure
Sorry for it being so long but that question was kinda tricky, hope you understand
If you need to get the angle that you've question marked, simply subtract it from 90 degrees.May/June 2007 - Question Paper 2 - Question 4 - Part (d)(i) and (ii)
I've tried till here, but I don't know how to get the angle ? Maybe my diagram is wrong?
(I know its not neat
QP: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s07_qp_2.pdf
MS: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s07_ms_2.pdf
Thanks in advance.
For 4b you should just think of the springs as resistors (like resistors in parallel and in series) the two springs in the first box of the question are in series and the two springs in the second box are in parallel. Now in series, you can say (just like how you find total resistance of 2 resistors in series) the extension is e + e = 2e (if you want to take it as resistors then you can say that resistance of each is e, so total resistance would be 2e). Its the same for all of them, just take them as resistors. Now to find k for each, you just use the equation F=kx, and use the respective extensions that you have calculated for each arrangement.
For number 5 it was a real challenge, especially part (b), but i think i got it (not sure if i am right though), i dont think i need to explain (a) right? Ok so part be, first calculate path difference, to do this first find the distance S2M (distance from S2 to M) using Pythagoras, then the path difference would be S2M - S1M = 128 - 100 = 28 (path difference is basically the difference that each wave has to travel, as the wave from S1 only travels 100 cm and wave from S2 travels 128 cm). Now for the intensity of sound to be 0 (a minima) the path difference should be (n +0.5)(lamda). So we have the speed (330) and 2 frequencies (1 kHz and 4kHz) so calculate 2 values of lamda using both these 2 frequencies, you will get 33 cm and 8.25 cm. Now after this part i am a bit less sure
Sorry for it being so long but that question was kinda tricky, hope you understand
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s03_qp_2.pdf
please help me for no. 3(a)(ii) and b(i)
Thanks
No one is here to help me...?
Use displacement/time at each of the times 20,40,60,80,100 keep in mind that after 50s velocity is negative. Plot values of velocity, draw your graph. DoneNo one is here to help me...?
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