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exactlyhttp://www.xtremepapers.com/community/attachments/diode-png.9242/
ow cool tx...pls just check...is this what you mean? i got it from one of the older threads.........ow g'luck for your p5!
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exactlyhttp://www.xtremepapers.com/community/attachments/diode-png.9242/
ow cool tx...pls just check...is this what you mean? i got it from one of the older threads.........ow g'luck for your p5!
exactly
This is the same as question 27, p11 of the same session. Inboxed you already
HELP NEEDED GUYS....!!!! AS LEVEL PHYSICS
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_1.pdf
CONFUSED IN QUESTIONS (37) PLEASE TELL ME IN DEATIL
(33) (31)(12) (24) (27) AND (28)
YOUR HELP WILL BE HUMBLY APPRECIATED..!!!!
HELP NEEDED GUYS....!!!! AS LEVEL PHYSICS
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_1.pdf
CONFUSED IN QUESTIONS (37) PLEASE TELL ME IN DEATIL
(33) (31)(12) (24) (27) AND (28)
YOUR HELP WILL BE HUMBLY APPRECIATED..!!!!
ohhh!!! thanksThis is the same as question 27, p11 of the same session. Inboxed you already
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_1.pdf
CONFUSED IN QUESTIONS (37) PLEASE TELL ME IN DEATIL
(33) (31)(12) (24) (27) AND (28)
YOUR HELP WILL BE HUMBLY APPRECIATED..!!!!
ok what about question (37)??Question 12:
momentum is conserved
momentum = p =mass x velocity
initial total momentum = (3m x v) + (m x -2v) = mv
as they stick together after collision, their velocity after collision is the same
total final momentum = (3m + m) x velocity = mv
4m x velocity = mv
velocity = v/4
Question 24:
if frequency is halved, the period is doubled as f=1/T
--> time taken for 1 complete cycle is doubled
intensity ∝ (amplitude^2)
amplitude ∝ √intensity
if intensity is doubled, thus the new amplitude is √2= 1.4
thus it's option B
this is 2012can some one help me with these questions.. thanks in advance
may june 2013 qp 11
no 19,20 $27..
this is 2012
19. E=Stress/Strain =3x1o^8/5% =3x10^8/0.05=6x10^9sorry dude that is may june 2010
20. Spring constant k=F/e.... think abt da gradient of the graph.... k=6/(1oo-70)x10^-3=200Nm^-1this is 2012
27. Work done in a circular path=0can some one help me with these questions.. thanks in advance
may june 2013 qp 11
no 19,20 $27..
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