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yes. SO taking the difference, (x+h)- (x-h) = 2hThen left tube will have height of x-h. and the right tube will have x + h right???? and now how come the difference is 2h ?
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yes. SO taking the difference, (x+h)- (x-h) = 2hThen left tube will have height of x-h. and the right tube will have x + h right???? and now how come the difference is 2h ?
Holy shit.I didnt understand this for days . Thank you so much ,yes. SO taking the difference, (x+h)- (x-h) = 2h
Holy shit.I didnt understand this for days . Thank you so much ,
its okay. physic drives us mad sometimesHoly shit.I didnt understand this for days . Thank you so much ,
momentum is conserved so it should remain as mv
originally the liquid's height was h ...when heated it expands and the increase is h again ...so its =2hWhy does the height increase again ? Wont it be the same height. I agree the height increases by "h" in the right tube. but after that i dont understand.
erm, difference = right - left = x + h - (x - h) = 2hThen left tube will have height of x-h. and the right tube will have x + h right???? and now how come the difference is 2h ?
thx but dont ever say u're dumb! Good luck in ur exam!Thank you so much! You are a saviour for dumb people like me !!
Can somebody post explainations to http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w08_qp_1.pdf
Questions 1, 27: the answers are C for both. I got the answer but messed up the power in both
Question 24C and 36B
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_1.pdf
^ Can someone please help me with questions 7,10,14,17,30,40,36
Thaankyou!
thanks now i get it broerm, difference = right - left = x + h - (x - h) = 2h
or either way which u get -2h (u just wan the magnitude of difference anyway)
anyone knws how to solve this
22 A steel string on an electric guitar has the following properties.
diameter = 5.0 × 10–4
m
Young modulus = 2.0 × 1011
Pa
tension = 20 N
The string snaps, and contracts elastically.
By what percentage does a length l of a piece of the string contract?
A 5.1 × 10–4
% B 5.1 × 10–2
% C 1.3 × 10–4
% D 1.3 × 10–2
%
anyone knws how to solve this
22 A steel string on an electric guitar has the following properties.
diameter = 5.0 × 10–4
m
Young modulus = 2.0 × 1011
Pa
tension = 20 N
The string snaps, and contracts elastically.
By what percentage does a length l of a piece of the string contract?
A 5.1 × 10–4
% B 5.1 × 10–2
% C 1.3 × 10–4
% D 1.3 × 10–2
%
anyone knws how to solve this
22 A steel string on an electric guitar has the following properties.
diameter = 5.0 × 10–4
m
Young modulus = 2.0 × 1011
Pa
tension = 20 N
The string snaps, and contracts elastically.
By what percentage does a length l of a piece of the string contract?
A 5.1 × 10–4
% B 5.1 × 10–2
% C 1.3 × 10–4
% D 1.3 × 10–2
%
use the formula for E
E = F x L / delta L x A
rearrange to get the ratio delta L / L on one side (change in length / original length)
youll get >> delta L / L = F / E A (A = pi r ^2 )
= 20 / 2 x 10^11 x pi x (2.5 x 10^-4)^2
= 5.1 x 10^-4
multiply this by a 100 to get the %
5.1 x 10^-4 x 100 = 5.1 x 10^-2 %
you party crasher!
why did you multiply it with 100 and made me look like a total idiot?
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