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Need help .
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Physics: Post your doubts here!
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Use the formula, Force-Friction=mass * acceleration.
Force will be the the weight of the load that is pulling 8 kg load . now the F=2*9.81 =19.62 N
now Friction we are given which is 6.0 N.
now we are calculating the system's acceleration , so , the mass will be (8+2 ) =10 kg.
now ,
19.62 - 6 = 10 * acceleration
acceleration = 1.362
which is 1.4 m/s2
Can you please see this question that i have attached !
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I think answer should be D. When the liquid moves up the right tube, it actually moves down the left at the same distance. So for example, your right tube liquid increase by 10, your left tube decrease by 10. The h difference between both tubes is actually 20 which is twice of the actual distance moved...
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Can you please explain me how the h difference will be 20 ?? wont it be 10 ?
could you help me with some questions please.
Q4
Q23( Is it because E is the same no matter what the dimensions are?)
Q26
Q33
Q34
http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w11_qp_11.pdf
Thanks a lot
Q4
Q23( Is it because E is the same no matter what the dimensions are?)
Q26
Q33
Q34
http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w11_qp_11.pdf
Thanks a lot
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http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s08_qp_1.pdf
ques no.24, and 26 plsss!!
ques no.24, and 26 plsss!!
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you can solve this question in two ways : (2nd is recommended)
at first we know that X= lamda x d / a , so apply it for the first equation and take d=1
1 x10^-3 = 600 x 10 ^-9 x 1/ a a= 0.6 mm
in the second equation we knw that x = 3mm and d increses by 2 ..so notice that "by'" and "to" is in bold
1+2 = 3 m .......... so 3 x 10^-3 x a = 600 x 10 ^-9 x 3 again you get 0.6 mm
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[quote="Farru, post: 4 1.pdf
ques no.24, and 26 plsss!![/quote]
in 24 the answer is E since young modulus is property of material and the material stays the same so E is constant ...its a tricky question !
for 26: since I is proportional to a^2/x^2 ..... so increasing x by 2 gives us 4x^2 ....since x increases by 4 I decreses by 4 and hence amplitude decreses by 4 ......so you get 8-4 = 4µm
ques no.24, and 26 plsss!![/quote]
in 24 the answer is E since young modulus is property of material and the material stays the same so E is constant ...its a tricky question !
for 26: since I is proportional to a^2/x^2 ..... so increasing x by 2 gives us 4x^2 ....since x increases by 4 I decreses by 4 and hence amplitude decreses by 4 ......so you get 8-4 = 4µm
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first find the distance between tge screen and double slit the (d) so we get two equations
x=d x lamda /a
making a the subject
so a=d x lamda /1x10^-3 and 2nd equatiom we get a=(2+d) x lamda/3 x 10^-3
solving them simultaneously we get D and the put d in any equation and we get (A) fringe seperation note that A is constant ....
24) the youngs modulus, E is the same for the same material, regardless of the length and cross sectional area, etc.
the SAME STEEL is used, so E is the same
26) ok now the molecules at Q are 2r from the source
and Intensity is inversely proportional to the distance from the source
d = 2r >> Intensity x 1/ 2^2 = 1/4
if intensity is decreasing by 4, and intensity is directly proportional to the amplitude...
then the amplitude is decreased by the square root of 4 = 2, so amplitude x 1/2
amplitude Q = 8 x 1/2 = 4 micrometers
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in this question originally the pressure = rho g h ....when hieght incresed by h again p= rho g 2h
when the pressure increases, the column on the right moves up by, h and the column on the right moves down by h.
so the total change in height is 2h
p = rho x g x delta h = rho g 2h
ps. a little shortcut, it says the pressure increases, therefore the formula has to be something that would give a higher value for the pressure, keeping in mind that the original pressure is rho g h
A and B wouldn't, C is like the original pressure, only D would =P
please answer this: n10 12: qs 8(my answer is coming 0.49ms-2) can any1 help me plzz
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http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_w11_qp_12.pdf
question 10 need help urgently~!
From my knowledge, momentum is constant if there's no external force acting on a system, so p = mv for the truck, since p is constant, when m increases v decreases, but why does the velocity stays the same when the sand is released from the truck? (Mass of the truck decreases?)
question 10 need help urgently~!
From my knowledge, momentum is constant if there's no external force acting on a system, so p = mv for the truck, since p is constant, when m increases v decreases, but why does the velocity stays the same when the sand is released from the truck? (Mass of the truck decreases?)
ok when at Y, the body has traveled 40 m, in 12 seconds so the speed at Y is v = d / t = 40 / 12 = 3.3 ms^-1
this is going to be the initial speed for the length YZ
the speed at Z = d / t = 40 / 6 = 6.6 ms^-1
this is the final speed for the length YZ
now use v^2 = u^2 + 2as for YZ
(6.6)^2 = (3.3)^2 + 2 a (40)
a = 0.36 ms^-2
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for 18 : E= power output / input ... out put is already given ...for input you multiply fuel comsumption by energy content ..convert to SI units. to check wether you did it correct multiply with units and you'll get ______j /s that is the unit of power . (sorry i think this is not what you asked for , but anyhow might be useful for sm1 else)
question 24: since both wires of same material so E young modulus is same
equate equations for both
F is same
so , FL/ pi r^2 x1 = F 3L/ 4 pi r^2 x2 ........................you will get x2= 3/4 x1
question 34 :
