- Messages
- 6,440
- Reaction score
- 31,077
- Points
- 698
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s12_qp_22.pdf
can some one solve and explain this question summer 2012 paper 22 question 6 c i and ii
View attachment 24479
wavelength = 34 cm in the graph
ie distance from node to node = 34 cm = λ / 2
So, wavelength of the wave = 68 cm = 0.68 m
v = fλ ---> f = v/λ
So, f = 340/0.68
f = 500 Hz