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Physics: Post your doubts here!

TaffsAsLevel

TaffsAsLevel

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Soldier313 said:
but i think it is necessary to include it in the diagram as far as i know :/
Thanx though!
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Nope, "arrangement of apparatus and procedures to be followed" procedures can be described just by the apparatus for which quantity
 

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daredevil

daredevil

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in that 31 questions
Mishaa said:
Q25) Drawing the waveforms, l=1/4wavelength in X and l=1/2 wavelength in Y. As the speed of sound is constant, the ratios of the frequencies should be reciprocal to the ratio of wavelengths, that would be frequency of X:Y = 1:2. So frequency of Y is double of the frequency of X.
Q31) Conduction wires conduct due to mobile electrons, so C and D are incorrect. The movement of electrons random, so B is eliminated. A is correct.

3. Q23) I'm not entirely sure of this but the extension is denoted by W/k. Now P and Q have identical spring constants so total extenion = 2. Now PQ and R are taken in series so product over sum gives us the answer.

4. Q12) SOMEONE PLEASE SOLVE THIS FOR ME TOO.

5. Q12) R1 and R2 both act against the weight of the frame so their magnitude would be equal. T1 has a greater horizontal component than T2, the vertical one is in the same line of force as the weight and R for both and is not considered, so wire T1 is more tensed upp. More like how picture frames fall when you suspend them with too short a wire and they snap. Real life scenarios. ;)

And I had a powercut scheduled in the middle so the 3 seperate posts. Sorry. :p
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there is no current in the wire so what were you saying about the C and D being incorrect because curent only passes with mobile electrns?
 
Mishaa

Mishaa

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daredevil said:
in that 31 questions
there is no current in the wire so what were you saying about the C and D being incorrect because curent only passes with mobile electrns?
Click to expand...

Delocalised or 'mobile' electrons are called so because they are never stable or in a fixed place. They move about. That being my point here on eliminating the two options, Miss T. :p
 
Soldier313

Soldier313

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TaffsAsLevel said:
Nope, "arrangement of apparatus and procedures to be followed" procedures can be described just by the apparatus for which quantity
Click to expand...

Owhhh okay....hmmm.... although our teacher told us that it is necessary to include all the apparatus in the diagram!
Thanx a lot for clarifying that....
 
daredevil

daredevil

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Mishaa said:
Delocalised or 'mobile' electrons are called so because they are never stable or in a fixed place. They move about. That being my point here on eliminating the two options, Miss T. :p
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hahahaha.... Meeeesshhaa! :p thanksuu xD
 
daredevil

daredevil

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hela said:
http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_11.pdf Q12 A
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i got help from a friend on that one...
its 120a = 120g - T (its F=ma for LHS and T is tension) --> for the barrel

80a = T - 80g ---> for the man

adding the 2 equaitons u get
200a = 40g
a = 1.962 [whn u take g=10ms^-2]

man is level with the barrel when both have covered the same distance:
18/2 = 9m [acceleration is same for both so both have travelled same distance]

2as = v2 - u2
2(1.962)(9) = v^2
v = 5.94 = 6 [approx.]
 
Mairaxo

Mairaxo

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in paper 5 graph question .. do we hav 2 extrapolate the graph till origin or just til the points? i have no teacher so i need help !! :rolleyes: and how many significant figures for all answers?
 
H

hela

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Mishaa said:
Q25) Drawing the waveforms, l=1/4wavelength in X and l=1/2 wavelength in Y. As the speed of sound is constant, the ratios of the frequencies should be reciprocal to the ratio of wavelengths, that would be frequency of X:Y = 1:2. So frequency of Y is double of the frequency of X.
Q31) Conduction wires conduct due to mobile electrons, so C and D are incorrect. The movement of electrons random, so B is eliminated. A is correct.

3. Q23) I'm not entirely sure of this but the extension is denoted by W/k. Now P and Q have identical spring constants so total extenion = 2. Now PQ and R are taken in series so product over sum gives us the answer.

4. Q12) SOMEONE PLEASE SOLVE THIS FOR ME TOO.

5. Q12) R1 and R2 both act against the weight of the frame so their magnitude would be equal. T1 has a greater horizontal component than T2, the vertical one is in the same line of force as the weight and R for both and is not considered, so wire T1 is more tensed upp. More like how picture frames fall when you suspend them with too short a wire and they snap. Real life scenarios. ;)

And I had a powercut scheduled in the middle so the 3 seperate posts. Sorry. :p
Click to expand...

very very helpful thanks
 
A

Azfar94

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PHYSICS P5: plz tell me how to know the appropriate number of s.f and d.p for filling up the table in question 2?
 
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