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25. f - 1/2 lambda. So 1 lambda (2 loops) - x.
27. W=Vq, which is the same for all the charges.
35. E=I(r+R), so I=E/(r+R).
Yeah.. thnx.. but didnt get what u meant in Q27?
Can u also please do Nov 2010 P12 Q25 please?