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Physics: Post your doubts here!

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Can anyone plz clarify how to find percentage uncertainty of May june 2012 variant 2 ????
i understood neither of the methods of MS
:cry:
 
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Yeah.. thnx.. but didnt get what u meant in Q27?
Can u also please do Nov 2010 P12 Q25 please?

27. What I meant was that Work Done on a point charge equals to the voltage x the charge. The charge for all the four is the same.
25. In tube X, the fundamental frequency will be 1/4 lambda. In tube Y, it'll be 1/2 lambda. f - 1/4, so x - 1/2.
 
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27. What I meant was that Work Done on a point charge equals to the voltage x the charge. The charge for all the four is the same.
25. In tube X, the fundamental frequency will be 1/4 lambda. In tube Y, it'll be 1/2 lambda. f - 1/4, so x - 1/2.

Ok.. got it Thanks a bunch :) :)
 
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Q 22 - 1st of all calculate mass* 6.02*10^23. this gives u the mass of all atoms in the crystal. then find the volume by dividing the mass u calculated by density. density=mass/volume. Then divide volume by 6.02*10^23. and find its cube root :)

Q25- Umm i guess extension will be the same as it obeys hookes law. Not sure though :/

Q26 - speed=2d/t. distance is muliplyd by 2 as its reflected so it travels the same distance twice. speed is that of light. so (2*150)/3*10^8 will give u 1 microsecond.

Q28- the two points are very apart by almost 1 full wave. Half wave apart is 180 degree but here the separation is greater so its 270.
Q35- sorry cant explain ! bad at this chap :/
Q38 - Just use a similar value for all resistors like 5ohm and calculate the combined resistance. If u use 5ohm then circuit 1 has resistance of 2ohm, 2 has 3 ohm. and 3 has 3.75 ohm :)

THANKS ALOT! :D
 
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the answer is A. This is beacuse pressure=hdg. so h=p/dg. pressure will now be 10% of atmospheric pressure. so (10/100)of atmospheric pressure. this gives atmospheric P/10 hence p/10dg :)
thnku so much sister for da help :)
 
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7. The component of acceleration is the acceleration due to gravity and that's the same always anywhere on Earth.
20. Choose a point and find the pressure due to P & Q at that same point. For example, any point on the second dotted line. The pressure due to Q will be = density of Q x g x h. The pressure due to P will be = density of Q x g x 2h. Cancel out g for both, you'll get density of Q = pressure/h, and density of P = pressure/2h.
25. Points on a wave vibrate up and down, and don't move to the right. A trough is travelling towards P, so P is going down.
 
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Q37 - its not D as no current will pass if both switch are open. Then its not even A as both are closed so current will be I. In B S2 is open and S1 is closed so current just flows in series so current is still I. In C current flows through parallel circuit as S1 is open and S2 closed and current is not equal in parallel so it will not be I :)
 
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Q37 - its not D as no current will pass if both switch are open. Then its not even A as both are closed so current will be I. In B S2 is open and S1 is closed so current just flows in series so current is still I. In C current flows through parallel circuit as S1 is open and S2 closed and current is not equal in parallel so it will not be I :)

okay you're a genius! thanks so much
 
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