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w04 q.no 20 Ans A
How?
How?
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Please explain the above posted mcqs pleaseyar its A, because, the distance between the charges does not change, so the work-done in moving the charge away or closer to each other is 0
remember.. work is only done when the distance 'between' the charges is changed
yar its A, because, the distance between the charges does not change, so the work-done in moving the charge away or closer to each other is 0
remember.. work is only done when the distance 'between' the charges is changed
Physic As oct 2010 / 12 mcq 22 and 34
May 2011/12 mcq 15,16,24
Pleaseee
w04 q.no 20 Ans A
How?
Use s is equal to half at^2Hi, would you mind solving november 2010 paper 12 QUEStion 8. It seems impossible please help
yaar seriously do this question some1 bcz i cant do it eitherHi, would you mind solving november 2010 paper 12 QUEStion 8. It seems impossible please help
Use s is equal to half at^2
ttwo equations form solve them simultaneously
First make of x to y
Then x to z
I told method aboveyaar seriously do this question some1 bcz i cant do it either
Pls help me !!!WOOW THAANK YOU I can't believe it should be that simple, I mean, I used YZ XZ and XY with all forms of equation silly me
Pls help me !!!
Somebody please helppppppppp these are my problems don't have any link pls
Physic As oct 2010 / 12 mcq 22 and 34
May 2011/12 mcq 15,16,24
May 2011/ mcq 14,15
Oct2011/13 mcq 17,25
Oct 2011/12 mcq 26
May 2012/12 mcq 5
i found the acce for both now wht do i do...i m nt getting da ans...if u explain plzzzUse s is equal to half at^2
ttwo equations form solve them simultaneously
First make of x to y
Then x to z
acce for both? how can u find that? the speed for each was constant. acceleration occurred from one motion to the other onlyi found the acce for both now wht do i do...i m nt getting da ans...if u explain plzzz
but he said to make 2 equations thats why....acce for both? how can u find that? the speed for each was constant. acceleration occurred from one motion to the other only
but he said to make 2 equations thats why....
can u shw me the calculation..
sorry but i m nt still getting....wht 40=12v+7240=12v+72a
80=18v+162a let v subject find a
s=ut+1/2 at^2
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