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May someone explain Q6(d) to me from the following paper? http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s10_qp_22.pdf
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If you know how to do the rest of the question can you explain it to me?May someone explain Q6(d) to me from the following paper? http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_22.pdf
when S2 is closed the "path of least resistance" will take up most of the current
so the current would flow through S2 rather than through B cause here B has resistance
for (i) we use power= VI
we don't have I so we replace I with V/R which we take from the equation R=V/I
power=v^2/r
R=38.4
ii) they are talking about total poser
so if S1 open there is no power you get this one right because the circuit is not complete
S1 and S2 closed as i said current always takes easier path so it will not go through B so in P=IV I=O the P is also 0 for B but then the current flows through A so its 1.5k+0=1.5k
if all of them are closed here again we will take power of B as 0 and if you see we have A and C in parallel Total power=P1+P2......... SO 1.5+1.5
S1 is closed so so we have A and B in series 1/total power = 1/p1 + 1/p2 +............
so 1/total power= 1/1.5 +1/1.5
total power =0.75
here s1 and S3 are closed so we have A and B parallel to C ie (AB) parallel to C for parallel Total power=P1+P2.........
and we already found AB which is 0.75 so now we just need to add 1.5
Q3 b part i First Calculate the height by which the ball is raised..use cos()
I solved it, anyways thanks a lotQ3 b part i First Calculate the height by which the ball is raised..use cos()
Then calculate the energy using mgh
part ii Calculate the moment by force x perpendicular distance
the perpendicular distance is found by sin()
Stationary waves are different from progressive waves in a number of respects:
There is no energy transfer along a stationary wave.
Within a half wavelength (one loop of a standing wave) all the particles vibrate in phase and they are all exactly out of phase (180° phase difference) with all the particles in the adjacent loop.
View attachment 37948 View attachment 37948
The amplitude of vibration varies with position within the loop.
There are nodes where the displacement is always zero and antinodes that vibrate with the same maximum amplitude.
The wavelength of a stationary wave is twice the distance between two adjacent nodes or antinodes.
Neighbouring nodes or antinodes are separated by lamda/2.
If you know how to do the rest of the question can you explain it to me?
Can someone explain how a potentiometer works in general?
I would also like someone to explain Q 6 part d from this paper: http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_22.pdf
Thank you in advance.
People are so helpful over here!
WelcomeT
Thank you for this!
Welcome
Inbox me.. same link.. I will need some time I am busy though.Hey, do you understand how potentiometers work? If you do, may you explain question 6 part d to me from:
http://papers.xtremepapers.com/CIE/Cambriidge International A and AS Level/Physics (9702)/9702_s10_qp_22.pdf
Hey, do you understand how potentiometers work? If you do, may you explain question 6 part d to me from:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s10_qp_22.pdf
Potentiometer is another name for the potential divider as the name gives us the hint that it divides the potential difference ...,,about question 6 part d I think the voltage through both points is not same because the current flowing through them has also divide and isnt equal so thats y even if we connect it half way to AB the voltage wont be same :/ I think
Well bro, I am not aware of your quesion, but to calculate pd, U need Current. But If you have other way then, do tell me.In order to calculate the pd across AC, do we have to look at the current that passes through the ammeter or the wire AC itself? (I am confused.)
Well bro, I am not aware of your quesion, but to calculate pd, U need Current. But If you have other way then, do tell me.
Well bro, I am not aware of your quesion, but to calculate pd, U need Current. But If you have other way then, do tell me.
well, which question ?For this particular question, do we need the current that passes through the ammeter or the current that passes through the wire AC? They would be different. These two currents would be less than the current that passes through CB. I think.
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