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Physics: Post your doubts here!

Snow Angel

Snow Angel

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Thought blocker

Thought blocker

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Snow Angel said:
can u please help with how to do the 10th question from this. please explain if u do get the answer exactly. please reply as soon as possible. Thanks in advance

qp: http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_13.pdf

ms: http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_ms_13.pdf
Click to expand...
we'll take this problem in terms of the forces acting on the barrel and the man
for the barrel: the force due to the barrel - the tension in the rope(T) = ma (because the barrel move's down, the force due to the barrel is greater than the tension)
(120*10) - T = 120a (we dont know the acceleration of the man and the barrel)
for the man: the tension (T) - the force due to the man = ma
T - (80*a) = 80a
find the value of a using simultaneous equations, which is 2 ms^-2
using v^2=u^2 + 2as
find the final velocity of the man at 9 m, taking u as 0 ms^-1

Credit-- > IGCSE O/L student
 
♣♠ Magnanimous ♣♠

♣♠ Magnanimous ♣♠

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Thought blocker said:
we'll take this problem in terms of the forces acting on the barrel and the man
for the barrel: the force due to the barrel - the tension in the rope(T) = ma (because the barrel move's down, the force due to the barrel is greater than the tension)
(120*10) - T = 120a (we dont know the acceleration of the man and the barrel)
for the man: the tension (T) - the force due to the man = ma
T - (80*a) = 80a
find the value of a using simultaneous equations, which is 2 ms^-2
using v^2=u^2 + 2as
find the final velocity of the man at 9 m, taking u as 0 ms^-1
Click to expand...
ur pc is working properly now. huh.
 
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