Physics: Post your doubts here!

[Snow Angel]

what

do i do? then

can u please help with how to do the 10th question from this. please explain if u do get the answer exactly. please reply as soon as possible. Thanks in advance

qp: http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_13.pdf

ms: http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_ms_13.pdf

 

[Snow Angel]

View attachment 38192

can u please help with how to do the 10th question from this. please explain if u do get the answer exactly. please reply as soon as possible. Thanks in advance

qp: http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_13.pdf

ms: http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_ms_13.pdf

 

[Thought blocker]

can u please help with how to do the 10th question from this. please explain if u do get the answer exactly. please reply as soon as possible. Thanks in advance

qp: http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_13.pdf

ms: http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_ms_13.pdf

we'll take this problem in terms of the forces acting on the barrel and the man
for the barrel: the force due to the barrel - the tension in the rope(T) = ma (because the barrel move's down, the force due to the barrel is greater than the tension)
(120*10) - T = 120a (we dont know the acceleration of the man and the barrel)
for the man: the tension (T) - the force due to the man = ma
T - (80*a) = 80a
find the value of a using simultaneous equations, which is 2 ms^-2
using v^2=u^2 + 2as
find the final velocity of the man at 9 m, taking u as 0 ms^-1

Credit-- > IGCSE O/L student

 

[♣♠ Magnanimous ♣♠]

we'll take this problem in terms of the forces acting on the barrel and the man
for the barrel: the force due to the barrel - the tension in the rope(T) = ma (because the barrel move's down, the force due to the barrel is greater than the tension)
(120*10) - T = 120a (we dont know the acceleration of the man and the barrel)
for the man: the tension (T) - the force due to the man = ma
T - (80*a) = 80a
find the value of a using simultaneous equations, which is 2 ms^-2
using v^2=u^2 + 2as
find the final velocity of the man at 9 m, taking u as 0 ms^-1

ur pc is working properly now. huh.

 

[Thought blocker]

ur pc is working properly now. huh.

Yeah, I did replied you, open your ID

 

[♣♠ Magnanimous ♣♠]

Yeah, I did replied you, open your ID

which? yahoo or skype?

 

[Thought blocker]

which? yahoo or skype?

skype Well do not post anything here its for doubts

 

[♣♠ Magnanimous ♣♠]

okay

skype Well do not post anything here its for doubts

.

 

[Suchal Riaz]

okay

.

It was a doubt wasn't it?

 

[♣♠ Magnanimous ♣♠]

It was a doubt wasn't it?

yup.

 

[Snow Angel]

thank you very much, but why do we 9 m for the displacement?

please do help in the ffuture as well

 

[Thought blocker]

thank you very much, but why do we 9 m for the displacement?

please do help in the ffuture as well

Suchal Riaz h/2 ?

 

[Snow Angel]

Suchal Riaz h/2 ?

y?

 

[Thought blocker]

y?

ask suchal I am too asking him

 

[Snow Angel]

ask suchal I am too asking him

ok

 

[Snow Angel]

ok

then please ask and tell

 

[Thought blocker]

then please ask and tell

He will quote you dw

 

[asma tareen]

It asked when it reached half the height

 

[Thought blocker]

It asked when it reached half the height

lol, I didn't read the question. I'am silly.

 

[asma tareen]

lol, I didn't read the question. I'am silly.

Neither did I