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Physics: Post your doubts here!

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For a single discharge , whats the average potential difference ?
it should be 1.6 , but the answer is 3.2
 
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Q17 As the reading of gavanometer is zero so the pd across that part of wire = E2 as we know the length so we can find pd/length using E2/XT. we already know XT and only need E2. (there are many ways to calculate that but for other methods more than one readings are required)
Q19 percentage uncertainty = error/reading as the reading increase the %uncertainty decrease. so it least near 100 C
 
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Q 21
power = work done/sec = IV = 200*6000 = 1200000 W
change in Potential energy/sec = mgh/sec =(m/sec)*gh = 500KgS- * 9.81ms-2 * 300m = 1471500W
efficiency = 1200000/1471500 = 81.5%
D
Q23
extension = F/k =W/k

k of parallel springs add together: 2k
springs in series add like resistors in parallel: 1/2+1/3 = 1/k, k=6/5

e=f/(6/5k) = 5W/6k
Q25
length = 3λ
speed = c
time = length/speed = 3λ/c
 
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