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Physics: Post your doubts here!

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Maximum speed = Upper limit of distance/Lower limit of time = 40.1/2.55 ≈ 16.4
Minimum speed = Lower limit of distance/Upper limit of time = 39.9/2.45 ≈ 15.6
Range of uncertainty = (Maximum - Minimum)/2 = (16.4 - 15.6)/2 = ± 0.4 m/s
Answer : C
Hadi, is there any other way ?
I do something completely different than you did.
So I mean, do you solve uncertainty questions like this only ?
 
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This concerns values you need to keep in memory unless they are on the data sheets, i'm not sure. Either ways, visible light falls in the range of
400 nm< λ < 700 nm. We can take any value in this range to represent out wavelength. Suppose we take 600 nm.
Then, the number of wavelengths in 1 meter = 1 / (600 * 10^-9) = 1.6667 * 10^6. So our answer is closest to B. Therefore, that's our answer.
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244cjgg.jpg

Thaaaaannkkk youu soo much :D :D
Dude can you PLEASE gime the estimates of the wavelengths .. If u've got 'em written.. Cuz I guess they're quite IMp in multiple choice papers.. :)
 
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B
24)
This concerns values you need to keep in memory unless they are on the data sheets, i'm not sure. Either ways, visible light falls in the range of
400 nm< λ < 700 nm. We can take any value in this range to represent out wavelength. Suppose we take 600 nm.
Then, the number of wavelengths in 1 meter = 1 / (600 * 10^-9) = 1.6667 * 10^6. So our answer is closest to B. Therefore, that's our answer.
29)
244cjgg.jpg
but dude,, why do we divide with 2 ?? As in k by 2 ?:$
 
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