- Messages
- 375
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Thought blockerQuestion 3, 4 , 5 , 8 , 11 , 14 , 15 , 19 , 24 , 33 , 35 , 37 , 38 PLEASEEEE!http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w13_qp_12.pdf
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Thought blockerQuestion 3, 4 , 5 , 8 , 11 , 14 , 15 , 19 , 24 , 33 , 35 , 37 , 38 PLEASEEEE!http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w13_qp_12.pdf
Please now I want to do my preparation... I'll solve it at night...
attatchment 4251Question ?
0.2 ?View attachment 45251 hey where am i going wrong?
i did it like this:- net emf=3-1.2=1.8V
V1=9/27*1.8=0.6V
0.6/9=0.067...y is my ans wrong?
.YEA//HW?0.2 ?
Here Resistors are connected in parallel, so there will be different currents in the circuit....YEA//HW?
thnks ...(silly me..:s)Here Resistors are connected in parallel, so there will be different currents in the circuit...
we are asked for the 9Ω resistor
so I = V/R
I = (3-1.2) / 9 = 0.2A
Help Student12 Please.thnks ...(silly me..:s)
Do some of them at least or by tonight.. :/ i know you have to prepare.Help Student12 Please.
yeah will do it tonightDo some of them at least or by tonight.. :/ i know you have to prepare.
LAST ANSWER NOW!!! BYEhttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w12_qp_13.pdf
question 21
thought blocker????
Thanksyeah will do it tonight
wait.. m gonna solve them... but i need sumtymDo some of them at least or by tonight.. :/ i know you have to prepare.
Ep = mgh = (h/4) ( h/2 is the height from m the midpoint to the depth)= mgh/4
constant then the kinetic energy would be zero...as it loses gpe....so only option left is Bhttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w12_qp_13.pdf
question 21
thought blocker????
thnksEp = mgh = (h/4) ( h/2 is the height from m the midpoint to the depth)= mgh/4
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