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this is what marking scheme says:-
(change in momentum = 1.2 (4.0 + 0.8) ....................................... C2
(correct values, 1 mark; correct sign {values added}, 1 mark )
= 5.76 N s …(allow 5.8) .....)
now the question is why positive sign so i guess the answer to this is that 4 m/s is the initial velocity and -0.8 is the final velocity so it will be 1.2( 4 - (-0.8) = 5.76 Nm
ooooooo brother its 5.76 NmBut the marking scheme states it to be +57.6
Also it states the working to be 1.2(4+0.8)
Here:http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_s09_ms_2.pdf
this is what marking scheme says:-
(change in momentum = 1.2 (4.0 + 0.8) ....................................... C2
(correct values, 1 mark; correct sign {values added}, 1 mark )
= 5.76 N s …(allow 5.8) .....)
now the question is why positive sign so i guess the answer to this is that 4 m/s is the initial velocity and -0.8 is the final velocity so it will be 1.2( 4 - (-0.8) = 5.76 Nm